Javascript 如何将数据传递给cron作业并保存它_Javascript_Python_Flask_Cookies_Jobs

Javascript 如何将数据传递给cron作业并保存它

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Javascript 如何将数据传递给cron作业并保存它,javascript,python,flask,cookies,jobs,Javascript,Python,Flask,Cookies,Jobs,我想运行一个cron作业，一旦用户进行身份验证，它将获取用户的电子邮件地址并将其传递给cron作业，以发出POST请求，刷新用户的accessToken，从而用户可以保持身份验证。然后作业必须将其发送到客户端，以便客户端可以将其保存为cookie，以便我的chrome扩展可以读取它 routes.py： def accessTokenRefresher(): user = User.query.filter_by(email=UserEmail).first() thecrede

我想运行一个cron作业，一旦用户进行身份验证，它将获取用户的电子邮件地址并将其传递给cron作业，以发出POST请求，刷新用户的accessToken，从而用户可以保持身份验证。然后作业必须将其发送到客户端，以便客户端可以将其保存为cookie，以便我的chrome扩展可以读取它

routes.py：

def accessTokenRefresher():
    user = User.query.filter_by(email=UserEmail).first()
    thecredentials = { 
            'client_id': os.getenv('client_id'),
            'client_secret':os.getenv('client_secret'),
            'refresh_token':user.refresh,
            'grant_type': 'refresh_token',
        }    
    req = requests.post(url='https://oauth2.googleapis.com/token', data = thecredentials)
    req_ = req.json()
    token = req_["access_token"]
    print(token)
    return render_template('/accounts/token.html',token = token)
scheduler = BackgroundScheduler()
scheduler.add_job(func=accessTokenRefresher, trigger="interval", seconds=10) 
scheduler.start()

token.html：

<html>
    <h1>{{token}}</h1>
    <script type="text/javascript">

        function setCookie(name,token) {
            console.log('the cookie is ' + token)
            var expires = "";
            var oldDate = new Date();
            var newDateObj = new Date(oldDate.getTime() + 2*60000); 
            expires = "; expires=" + newDateObj.toUTCString();
            document.cookie = name + "=" + (token || "")  + expires + "; path=/";
               
        }
        setCookie('user_token', '{{token}}')
        </script>
</html>

&如果我将电子邮件传递给该功能，它将第一次工作&而不是每小时，永远。因为我不想让用户每次都进行身份验证，而是让cron负责

This typically means that you attempted to use functionality that needed
an active HTTP request. Consult the documentation on testing for
information about how to avoid this problem.