需要帮助在3D matlab中存储值和绘图吗

我正在创建一个matlab脚本，稍后将导入solidworks。我需要帮助存储循环方程中的值。下面是代码。我想在3D中创建椭圆，沿z轴以逐渐减小的半径隔开。如何存储输入的数据，然后用3D打印该数据

% 1TotalMesurments

prompt={'Enter the number of measurements taken', ...
        'Enter the distance between each measurement in inches'}

name = 'Step 1 total measurements and distance';

answer = inputdlg(prompt, name);

s= str2double(answer{1}); %Number of measurement
d= str2double(answer{2}); %Distance between each measurement

% 3LoopOfCircumferenceAndWidth

for i=1:s %s is predefined in 1TotalMeasurments

    % 2Circumferenceandwidth%

    prompt = {'Enter the Circumference of 1st point', ...
              'Enter the approximate width of your arm'};

    title = 'Circumference and width of arm at first point';

    answer = inputdlg(prompt, title);

    C = str2double(answer{1}); %Circumference
    X = str2double(answer{2}); %width radius value
    Y=(((C./(2.*pi))^2).*2)-(X./2)^2; %height radius value

    plot(X,Y)

    hold on
end

---

您需要使用数值数组或单元格数组来存储循环内部的值。我们首先要初始化数组以在循环外部存储数据，然后在循环的每次迭代中填充它们。这是我所说的大概意思

% Pre-allocate the array based on the total # of measurements
Cvalues = zeros(s, 1);
Xvalues = zeros(s, 1);
Yvalues = zeros(s, 1);

for k = 1:s 
    prompt = {'Enter the Circumference of 1st point', ...
              'Enter the approximate width of your arm'};

    title = 'Circumference and width of arm at first point';

    answer = inputdlg(prompt, title);

    C = str2double(answer{1}); %Circumference
    X = str2double(answer{2}); %width radius value
    Y = (((C./(2.*pi))^2).*2)-(X./2)^2; %height radius value

    % Assign them to your arrays for storage
    Cvalues(k) = C;
    Xvalues(k) = X;
    Yvalues(k) = Y;

    plot(X,Y)

    hold on
end

---

如果

C

、

X

和

Y

在循环的不同迭代中大小不同（您的情况似乎不是这样），则需要使用单元格数组而不是数字数组。

您需要使用数字数组或单元格数组来存储循环内部的值。我们首先要初始化数组以在循环外部存储数据，然后在循环的每次迭代中填充它们。这是我所说的大概意思

% Pre-allocate the array based on the total # of measurements
Cvalues = zeros(s, 1);
Xvalues = zeros(s, 1);
Yvalues = zeros(s, 1);

for k = 1:s 
    prompt = {'Enter the Circumference of 1st point', ...
              'Enter the approximate width of your arm'};

    title = 'Circumference and width of arm at first point';

    answer = inputdlg(prompt, title);

    C = str2double(answer{1}); %Circumference
    X = str2double(answer{2}); %width radius value
    Y = (((C./(2.*pi))^2).*2)-(X./2)^2; %height radius value

    % Assign them to your arrays for storage
    Cvalues(k) = C;
    Xvalues(k) = X;
    Yvalues(k) = Y;

    plot(X,Y)

    hold on
end

如果

C

、

X

和

Y

在循环的不同迭代中大小不同（您的情况似乎不是这样），那么您可能希望使用单元格数组而不是数字数组