Ms access 对有意义报告的查询

示例查询结果

 Employee_Last   Employee_First   RoleName   CourseName   CourseStart   CourseEnd   Attended  
 Ables           Christopher      ServiceMGR OTC Training 12/1/11       12/1/11     Yes  
 Ables           Christopher      ServiceMGR                                        No
 Ables           Christopher      ServiceMGR OTC Part 1   12/5/11       12/5/11     Yes  
 Ables           Christopher      AssetShipper                                      No  
 Ables           Christopher      AssetShipper                                      No  
 Ables           Christopher      AssetShipper                                      No  
 Ables           Christopher      AssetShipper                                      No  

这些是我从查询中得到的结果，有许多查询都是从表中提取来获取这些数据的。数据库已规范化。
我想要创建的报告是一个关注参与者的报告

 If Yes 
          Show all of the line item from the query 
 Else If   
          If RoleName is listed previously for a specific employee and attended =  
             yes on that line item(ie: Ables | Christopher | ServiceMGR | No -- should not be seen)  
             Don't Show 
          Else If RoleName is listed previously for a specific employee and Attended = No  
             Only Show the item once(ie: Should only see Ables | Christopher | AssetShipper | No)  
          End If  
 End IF

因此，可能需要另一个查询来过滤此查询。我从样本数据中查找的报告应如下所示：

 Employee_Last   Employee_First   RoleName   CourseName   CourseStart   CourseEnd   Attended  
 Ables           Christopher      ServiceMGR OTC Training 12/1/11       12/1/11     Yes  
 Ables           Christopher      ServiceMGR OTC Part 1   12/5/11       12/5/11     Yes  
 Ables           Christopher      AssetShipper                                      No  

---

希望你明白我在说什么。我对如何隐藏和显示记录做了一些研究，但我对Access不够熟悉。因此，基本上我需要过滤Attended=No，以使其对最终用户有意义。

也许有以下几行：

SELECT employee_last,
       employee_first,
       rolename,
       coursename,
       coursestart,
       courseend,
       attended
FROM   attend
WHERE  attended = "Yes"
UNION
SELECT DISTINCT b.employee_last,
                b.employee_first,
                b.rolename,
                NULL AS coursename,
                NULL AS coursestart,
                NULL AS courseend,
                b.attended
FROM   (SELECT employee_last,
               employee_first,
               rolename
        FROM   attend
        WHERE  attended = "Yes") AS a
       RIGHT JOIN (SELECT employee_last,
                          employee_first,
                          rolename,
                          attended
                   FROM   attend
                   WHERE  attended = "No") AS b
         ON ( a.rolename = b.rolename )
            AND ( a.employee_first = b.employee_first )
            AND ( a.employee_last = b.employee_last )
WHERE  (( ( a.employee_last ) IS NULL )) 

---

我们将对此进行观察，并在操纵表名后报告像符咒一样的反向工作。很不错的！非常感谢。我会投赞成票，但我的分数不够。哈