Mysql 内部联接只显示表中的第一行

我的数据库中有以下数据：

渣打银行：

---------------------------------
|   id    |   type   |   name   |
|-------------------------------|  
|    1    |    1     |   One    |
|    2    |    1     |   Two    |
|    3    |    2     |  Three   |
|    4    |    3     |   Four   |
---------------------------------

scu_声明：

---------------------------------
|   id    |   code   |   mutation   |
|-----------------------------------|  
|    1    |    1     |     100      |
|    2    |    1     |     200      |
|    3    |    2     |     500      |
|    4    |    1     |     500      |
-------------------------------------

SELECT      scu_banks.type,
            scu_banks.name, 
            CONCAT('€ ', FORMAT(IFNULL(SUM(scu_statement.mutations), 0),2)) AS total, 
            scu_banks.id
FROM        scu_banks
INNER JOIN  scu_statement
ON          scu_banks.id = scu_statement.code

我要做的是选择表

scu\u banks

中的所有行，并显示突变总数。数据应表示为：

--------------------------------------------------------------
| scu_banks.type | scu_banks.name |   total   | scu_banks.id |
--------------------------------------------------------------
|       1        |      One       | € 800.00  |      1       |
|       1        |      Two       | € 500.00  |      2       |
|       2        |     Three      | €   0.00  |      3       |
|       3        |      Four      | €   0.00  |      4       |
--------------------------------------------------------------

当我运行sql语句时，我得到以下数据：

---------------------------------------------------------------
| scu_banks.type | scu_banks.name |    total   | scu_banks.id |
--------------------------------------------------------------
|       1        |      One       | € 1300.00  |      1       |
---------------------------------------------------------------

我在这种情况下得到的数据是不正确的。1300.00欧元是表

scu声明中所有突变的总和。该语句也不显示数据库中的其他行

有人知道我的sql语句有什么问题吗

以下是我的sql语句：

---------------------------------
|   id    |   code   |   mutation   |
|-----------------------------------|  
|    1    |    1     |     100      |
|    2    |    1     |     200      |
|    3    |    2     |     500      |
|    4    |    1     |     500      |
-------------------------------------

SELECT      scu_banks.type,
            scu_banks.name, 
            CONCAT('€ ', FORMAT(IFNULL(SUM(scu_statement.mutations), 0),2)) AS total, 
            scu_banks.id
FROM        scu_banks
INNER JOIN  scu_statement
ON          scu_banks.id = scu_statement.code

在子查询中进行聚合，然后将其左键连接到银行

SELECT b.type "scu_banks.type",
       b.name "scu_banks.name",
       concat('€ ', format(coalesce(x.mutation, 0), 2)) "total",
       b.id "scu_banks.id"
       FROM scu_banks b
            LEFT JOIN (SELECT s.code,
                              sum(s.mutation) mutation
                              FROM scu_statement s
                              GROUP BY s.code) x
                      ON x.code = b.id;

解释计算总计的逻辑。这些突变是什么？？还有xmen？你使用的是什么版本的mysql？