Php 将两个不同的查询合并为一个合并的foreach

我会尽力解释的。我有两个查询从MySQL中提取数据，一个从公园评论中提取数据，另一个从骑乘评论中提取数据。这两个查询都按查看日期排序

我在网页上想要的是一个按

审核日期排序的审核列表，因此停车审核和乘车审核将混合在一个列表中

几乎就像运行两个foreach循环，每个查询一个循环，但根据日期轮流执行

以下是两个问题：
乘车

$query4= 'SELECT review_id, review, tpf_reviews_rides.user, DATE_FORMAT(date_ridden, "%d %M %Y") AS Date_Ridden, DATE_FORMAT(review_date, "%d %M %Y") AS Review_Date, tpf_rides.name AS ride_name, rating, tpf_parks.name  AS park_name, country
FROM tpf_reviews_rides  

INNER JOIN tpf_rides ON tpf_reviews_rides.ride_id = tpf_rides.ride_id
INNER JOIN tpf_ratings_rides ON tpf_reviews_rides.rating_link = tpf_ratings_rides.rating_id  
INNER JOIN tpf_parks ON tpf_reviews_rides.park_id = tpf_parks.park_id

ORDER BY review_date DESC, review_id DESC LIMIT '.$start_from.' , '.$limit.'';

公园：

$query5= 'SELECT review_id, review, tpf_reviews_parks.user, DATE_FORMAT(date_visited, "%d %M %Y") AS Date_Visited, DATE_FORMAT(review_date, "%d %M %Y") AS Review_Date, rating, tpf_parks.name, country
FROM tpf_reviews_parks  

INNER JOIN tpf_ratings_parks ON tpf_reviews_parks.rating_link = tpf_ratings_parks.rating_id  
INNER JOIN tpf_parks ON tpf_reviews_parks.park_id = tpf_parks.park_id

ORDER BY review_date DESC, review_id DESC LIMIT '.$start_from.' , '.$limit.'';

这就是我分别显示结果的方式：
乘车：

foreach ($res4 AS $row4) { 
            printf('
            <h2 style="display:inline;">%s</h2> <h3 style="display:inline;">- %s, %s</h3>
            <h3>Rating - %sStars</h3>
            <h4>Submitted by %s on %s</h4>
            <p>%s</p>' . PHP_EOL, $row4['ride_name'], $row4['park_name'], $row4['country'], $row4['rating'], (htmlspecialchars($row4['user'], ENT_QUOTES, 'UTF-8')), $row4['Review_Date'], nl2br(htmlspecialchars($row4['review'], ENT_QUOTES, 'UTF-8')));

            if(!empty($row4['Date_Ridden'])){
            printf('<p>Date ridden: %s</p>' . PHP_EOL, $row4['Date_Ridden']);
            }

            printf('<a class="bloglink" href="#top">Back to Top</a>
            <hr>');

        }


    For PArks:

foreach ($res5 AS $row5) { 
    printf('
    <h2 style="display:inline;">%s</h2> <h3 style="display:inline;">- %s</h3>
    <h3>Rating - %sStars</h3>
    <h4>Submitted by %s on %s</h4>
    <p>%s</p>' . PHP_EOL, $row5['name'], $row5['country'], $row5['rating'], (htmlspecialchars($row5['user'], ENT_QUOTES, 'UTF-8')), $row5['Review_Date'], nl2br(htmlspecialchars($row5['review'], ENT_QUOTES, 'UTF-8')));

    if(!empty($row4['Date_Ridden'])){
    printf('<p>Date Visited: %s</p>' . PHP_EOL, $row4['Date_Visited']);
    }

    printf('<a class="bloglink" href="#top">Back to Top</a>
    <hr>');

}

foreach（$res4作为$row4）{
printf（'
%s-%s，%s
评级-%sStars
由%s在%s上提交
%s
'.PHP_EOL、$row4['ride_name']、$row4['park_name']、$row4['country']、$row4['rating']、（htmlspecialchars（$row4['user']，ENT_QUOTES，'UTF-8'）、$row4['Review_Date'，nl2br（htmlspecialchars（$row4['Review']，ENT_QUOTES，'UTF-8'））；
如果（！空（$row4['Date\u riden']））{
printf（“Date-rided:%s
”.PHP_-EOL，$row4['Date_-rided']）；
}
printf（'
”）；
}
公园：
foreach（$res5作为$row5）{
printf（'
%s-%s
评级-%sStars
由%s在%s上提交
%s
“.PHP_EOL，$row5['name']，$row5['country']，$row5['rating']，（htmlspecialchars（$row5['user'，entu QUOTES，'UTF-8'）），$row5['Review_Date'，nl2br（htmlspecialchars（$row5['Review'，entu QUOTES，'UTF-8'））；
如果（！空（$row4['Date\u riden']））{
printf（“访问日期：%s
”.PHP_EOL，$row4[“访问日期]）；
}
printf（'
”）；
}

为了使它更复杂，这一页是分页的。看看它，因为这两个查询非常相似，如果有一种方法可以在查询级别进行组合，那么这将是最好的，并且有助于保持分页代码的得体性。有人对我如何做到这一点有什么建议吗

谢谢
您可以使用合并两个select语句

请注意，如果表非常相似，则最好合并它们（不是在查询中，而是在实际表中）。我没有看到与
tpf\u reviews\u parks
相比，您的
tpf\u reviews\u骑行中有任何字段不完全相同。添加一列表示审核类型（骑乘或停车），您应该进行设置。它将简化查询和处理逻辑

SELECT
    type,
    review_id,
    review,
    user,
    Date_Event,
    Review_Date,
    ride_name,
    rating,
    park_name,
    country
FROM (
    SELECT
        'ride' as type,
        review_id,
        review,
        tpf_reviews_rides.user,
        DATE_FORMAT(date_ridden, "%d %M %Y") AS Date_Event,
        DATE_FORMAT(review_date, "%d %M %Y") AS Review_Date,
        tpf_rides.name AS ride_name,
        rating,
        tpf_parks.name AS park_name,
        country
    FROM
        tpf_reviews_rides  
        INNER JOIN tpf_rides ON tpf_reviews_rides.ride_id = tpf_rides.ride_id
        INNER JOIN tpf_ratings_rides ON tpf_reviews_rides.rating_link = tpf_ratings_rides.rating_id  
        INNER JOIN tpf_parks ON tpf_reviews_rides.park_id = tpf_parks.park_id

    UNION

    SELECT
        'park' as type,
        review_id,
        review,
        tpf_reviews_parks.user,
        DATE_FORMAT(date_visited, "%d %M %Y") AS Date_Event,
        DATE_FORMAT(review_date, "%d %M %Y") AS Review_Date,
        NULL as ride_name,
        rating,
        tpf_parks.name AS park_name,
        country
    FROM
        tpf_reviews_parks  
        INNER JOIN tpf_ratings_parks ON tpf_reviews_parks.rating_link = tpf_ratings_parks.rating_id  
        INNER JOIN tpf_parks ON tpf_reviews_parks.park_id = tpf_parks.park_id
) AS reviews
ORDER BY
    review_date DESC,
    review_id DESC
LIMIT ' . $start_from . ', ' . $limit;

我想在阅读了你的答案并进一步研究之后，我认为你是对的，我将合并这两个表格。谢谢