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PHP/MySQL while循环未解析_Php_Javascript_Ajax - Fatal编程技术网

PHP/MySQL while循环未解析

PHP/MySQL while循环未解析,php,javascript,ajax,Php,Javascript,Ajax,我修改了以下代码以进行连接,然后为以后的表单元素构建数组: $usersitems = ''; $db_connection = mysql_connect($dbhost,$dbuser,$dbpassword); if($db_connection && mysql_select_db($dbname,$db_connection)){ $usersquery = 'SELECT DISTINCT tablea.uid, tableb.FirstName, table

我修改了以下代码以进行连接,然后为以后的表单元素构建数组:

$usersitems = '';
$db_connection = mysql_connect($dbhost,$dbuser,$dbpassword);
if($db_connection && mysql_select_db($dbname,$db_connection)){
    $usersquery = 'SELECT DISTINCT tablea.uid, tableb.FirstName, tableb.LastName FROM tablea, tableb WHERE tablea.uid = tableb.EmpNo ORDER BY tablea.uid ASC';
    $users = mysql_query($usersquery,$db_connection);
    if($users){
        while ($user = mysql_fetch_array($users, MYSQL_NUM)) {
            $usersitems .= '<option value="'.$user[0].'">'.$user[0].'- '.$user[1].' '.$user[2].'</option>';  
        }
        mysql_free_result($users);
    }
    mysql_close($db_connection);
} 
现在突然间这不起作用了?我假设这是因为原始的“$user[0]”没有在选项中查找值=“”。$user[0]”。如何修改此项?

将代码更改为:

uid = $("#user_id").val();
这将返回所选选项的值

这也适用于您以前的选项处理方式。如果选项没有
属性,则默认使用文本。

将代码更改为:

uid = $("#user_id").val();
这将返回所选选项的值

这也适用于您以前的选项处理方式。如果选项没有
属性,则默认情况下使用文本

uid = $("#user_id").val();