Python 2.7 我能'；不要让我的玩家在Pygame上射击，因为上面写着：'；浮动'；对象没有属性'__获取项目'；

嗯。我只想在比赛中射出一些子弹。我尽了最大的努力，但我做不到

首先，我将项目符号的角度和位置存储在项目符号数组的列表中。第二，我用sin和cos给它速度，我把它的运动限制在640px和480px的循环中。然后我把它显示在player_x，player_y上

它应该从player_x，player_y开始，按照cos和sin法则行走，并在屏幕上破坏bordeline

但它显示了以下句子：

第53行
vel_x=math.cos（bullet[0]）*10
类型错误：“float”对象没有 属性'getitem'

这是代码

#
# Title: Shoot The Zombies
# Author(s): John Redbeard, ("http://john-redbeard.tumblr.com/")
# 

import pygame
from pygame.locals import *
import math

    # Initiate Pygame
pygame.init()
width, height = 640, 480
screen=pygame.display.set_mode((width, height))
pygame.display.set_caption("Shoot the Zombies")
fps = 60
fpsclock = pygame.time.Clock()

    # Load images
player = pygame.image.load("images/player.png")
player_x = 100
player_y = 100
posplayer_x = 0
posplayer_y = 0

grass = pygame.image.load("images/grass.png")

bullet = pygame.image.load("images/bullet.png")
bullets_array = []

target = pygame.image.load("images/target.png")

    # Main Loop Game
while True:

    pygame.mouse.set_visible(False)

    screen.fill(False)

    # Load on screen the grass in isometric way
    for x in range(width/grass.get_width()+1):
        for y in range(height/grass.get_height()+1):
            screen.blit(grass,(x*100,y*100))

    # Load on screen the rotated-positioned-player
    mouse_position = pygame.mouse.get_pos()
    angle = math.atan2(mouse_position[0] - player_x, mouse_position[1] - player_y)
    player_rotate = pygame.transform.rotate(player, 360+angle*57.29)
    player_position = (player_x - player_rotate.get_rect().width/2, player_y - player_rotate.get_rect().height/2)
    screen.blit(player_rotate, player_position)

    # load on screen the rotated-posioted-bullets
    for bullet in bullets_array:
        vel_x = math.cos(bullet[0])*10
        vel_y = math.sin(bullet[1])*10
        bullet[0] += vel_x
        bullet[1] += vel_y
        if bullet[0] >640 or bullet[1] > 480:
            bullets_array.remove(bullet)
        bullet1 = pygame.transform.rotate(bullet, 360+angle*57.29)
        screen.blit(bullet1, (player_x, player_y))

    # Load on screen the target
    screen.blit(target, (mouse_position))

    # Display window
    pygame.display.flip()

    # Run events
    for event in pygame.event.get():
        if event.type==pygame.QUIT:
            pygame.quit() 
            exit(False)

    # Event: W/A/S/D (Keyboard) moving player
        elif event.type == KEYDOWN:
            if event.key == K_w:
                posplayer_y -= 3
            elif event.key == K_a:
                posplayer_x -= 3
            elif event.key == K_s:
                posplayer_y += 3
            elif event.key == K_d:
                posplayer_x += 3

        elif event.type == KEYUP:
            if event.key == K_w:
                posplayer_y = 0
            elif event.key == K_a:
                posplayer_x = 0
            elif event.key == K_s:
                posplayer_y= 0
            elif event.key == K_d:
                posplayer_x = 0

    # Event: Mouse click shoot the bullet
        elif event.type == MOUSEBUTTONDOWN:
            bullets_array.append(math.atan2(mouse_position[0] - player_x, mouse_position[1] - player_y))

    player_x += posplayer_x
    player_y +=posplayer_y

    fpsclock.tick(fps)

---

您将

float

值添加到

项目符号\u数组中

：

bullets_array.append(math.atan2(mouse_position[0] - player_x, mouse_position[1] - player_y))

那只是一个电话；它产生一个浮点值

然后，您期望有两个值：

for bullet in bullets_array:
    vel_x = math.cos(bullet[0])*10
    vel_y = math.sin(bullet[1])*10

不能为浮点值编制索引

如果您希望有两个值，那么必须创建一个包含两个浮点的元组，而不是只添加一个浮点。你当然没有

将项目符号的角度和位置存储在项目符号数组的列表中

首先“bullet”是一个PNG文件，然后它是一个浮点数组中的一个项，然后你把这个浮点数组作为两个元素的数组bullet[0]和bullet[1]来使用？