Python 3.x Python3时间转换器(无效语法)
它表示无效语法是带有Python 3.x Python3时间转换器(无效语法),python-3.x,math,syntax,converters,invalid-argument,Python 3.x,Math,Syntax,Converters,Invalid Argument,它表示无效语法是带有if choice==“S”的行: 无效的语法是:在“A”后面 您好,您的语法似乎不正确,因为输入函数缺少右括号,我还为您的“choice”变量添加了一个字符串转换。错误在您的语法中: 错误出现在您的此行中: print("Choose the unit to convert to") print("Seconds = S") print("Minutes = M") print("Hours = H") var1 = 100 var2 = 10 var5 = 0 choi
if choice==“S”的行:
无效的语法是:在“A”后面
您好,您的语法似乎不正确,因为输入函数缺少右括号,我还为您的“choice”变量添加了一个字符串转换。错误在您的语法中: 错误出现在您的此行中:
print("Choose the unit to convert to")
print("Seconds = S")
print("Minutes = M")
print("Hours = H")
var1 = 100
var2 = 10
var5 = 0
choice = str(input("Enter (S/M/H):"))
print(type(choice))
if choice == "S":
var5 = (var1 / var2)
print("Awnser: "+str(var5))
你错过了一个)
试着让我简单地为您编写代码:
choice = input("Enter (S/M/H): "
您还需要在choice变量中添加Str
choice = input("Enter (S/M/H): "
print("Choose the unit to convert to")
print("Seconds = S")
print("Minutes = M")
print("Hours = H")
choice = str(input("Enter (S/M/H): "))
if choice == "S":
var5 = (var1 / var2)
print("Awnser:")