python新手获取错误name错误:name';员工名单';没有定义
但是,每当我运行这个程序时,它都会给我一个错误,说“ 第50行,适用于employeeList中的员工:名称错误:名称 未定义“employeeList” " 我将代码粘贴到pastebin上,因为stackoverflow正在从代码中删除缩进python新手获取错误name错误:name';员工名单';没有定义,python,Python,但是,每当我运行这个程序时,它都会给我一个错误,说“ 第50行,适用于employeeList中的员工:名称错误:名称 未定义“employeeList” " 我将代码粘贴到pastebin上,因为stackoverflow正在从代码中删除缩进 请帮助我,因为我明天就要交学期专题了你的代码很好:是你的缩进搞糟了: # starting of Employee class class Employee(object): def __init__(self): #declaring Cons
请帮助我,因为我明天就要交学期专题了你的代码很好:是你的缩进搞糟了:
# starting of Employee class
class Employee(object):
def __init__(self): #declaring Constructor
self.name = ""
self.iDnumber = ""
self.department = ""
self.jobTitle = ""
# setter methode for setting values to the class properties
def setName(self,name):
self.name=name
def setIDnumber(self,iDnumber):
self.iDnumber=iDnumber
def setDepartment(self,department):
self.department=department
def setJobTitle(self,jobTitle):
self.jobTitle=jobTitle
# getter methode for getting values of the class properties
def getName(self):
return self.name
def getIDnumber(self):
return self.iDnumber
def getDepartment(self):
return self.department
def getJobTitle(self):
return self.jobTitle
# methode which takes object as an argument and display its properties
def display(emp_object):
print("Name : ",emp_object.getName())
print("IDnumber : ",emp_object.getIDnumber())
print("Department : ",emp_object.getDepartment())
print("JobTitle : ",emp_object.getJobTitle())
# Main methode of the program
if __name__ == "__main__":
employeeList = [] #List to hold the Employee objects
emp1 = Employee()
emp2 = Employee()
emp3 = Employee()
# appending objects to the list
employeeList.append(emp1)
employeeList.append(emp2)
employeeList.append(emp3)
input()
# Initializing each objects of the list
for employee in employeeList:
emp_name = input("Enter your Name ")
employee.setName(emp_name)
emp_iDnumber = input("Enter your iDnumber ")
employee.setIDnumber(emp_iDnumber)
emp_department = input("Enter your Department ")
employee.setDepartment(emp_department)
emp_jobTitle = input("Enter your JobTitle ")
employee.setJobTitle(emp_jobTitle)
# Displaying each objects of the list
for emp_object in employeeList:
display(emp_object)
输出:
Enter your Name viki
Enter your iDnumber 1
Enter your Department a
Enter your JobTitle b
Enter your Name viki2
Enter your iDnumber 2
Enter your Department b
Enter your JobTitle c
Enter your Name viki3
Enter your iDnumber 3
Enter your Department a
Enter your JobTitle b
Name : viki
IDnumber : 1
Department : a
JobTitle : b
Name : viki2
IDnumber : 2
Department : b
JobTitle : c
Name : viki3
IDnumber : 3
Department : a
JobTitle : b
注:
使用方法名称,如get\u name
或set\u name
,而不是setName
。您还可以使用属性装饰器
:
附言:也请仔细阅读对你的问题的评论,在你完成这学期的学习后,有一些非常好的建议可以帮助你提高编码能力。你的缩进都搞砸了。。。这就是它不起作用的原因…谢谢你能帮上忙吗?我建议使用一个好的ide。。。像pycharm之类的东西。。。它将告诉您这些问题,并建议修复请参阅“”以获取缩进代码块的帮助。请(重新)阅读“”,然后将您的问题包括在内,这样即使在粘贴箱文本消失后,您的问题仍将对其他人有用。(注意:我怀疑这将以“”结尾,但它可能不会。)