Python 从二进制数组中逐行随机选择百分比？

我有一个二进制文件数组。。。我想要的是能够从每一行中选择一个特定的百分比。。。 f、 假设每行有100个，我想从第一行随机取回20%，从第二行随机取回10%， 第三名为40%，第四名为30%（当然全部为100%）

这很容易，只要在每一行上做随机选择（一个_idx，%）。问题是目标的位数也必须是100。。 i、 e.如果某些位重叠，并且随机选择选取了它们，则总数将不同于100位

另外，在每一行上，它应该尝试选择以前没有选择的位，至少作为一个选项

有什么想法吗

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例如，我用于直截了当的情况的代码（不考虑所选索引是否跨行重复，仅在一行内重复）：

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我只能挑那些。。这就是为什么我使用索引，使用字符串列表作为一种方便，而不是位数组，并获得4个样本

In [39]: data = ['10000101', 
    ...:         '11110000', 
    ...:         '00011000']                                                    

In [40]: idxs = random.sample(range(len(data[0])), 4)                           

In [41]: # 20% row 1, 30% row 2, 50% row 3                                      

In [42]: row_selections = random.choices(range(len(data)), [0.2, 0.3, 0.5], k=len(idxs))                                                               

In [43]: idxs                                                                   
Out[43]: [7, 3, 1, 4]

In [44]: row_selections                                                         
Out[44]: [0, 2, 0, 1]

In [45]: picks = [ data[r][c] for (r, c) in zip(row_selections, idxs)]          

In [46]: picks                                                                  
Out[46]: ['1', '1', '0', '0']

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好的，根据您的评论，这应该可以更好地作为一个示例，说明如何仅按比例从每个列表/数组中选择一个：

import random
a1= '10001010111110001101010101'
a2= '00101010001011010010100010'
a1 = [int(t) for t in a1]
a2 = [int(t) for t in a2]
a1_one_locations= [idx for idx, v in enumerate(a1) if v==1]
a2_one_locations= [idx for idx, v in enumerate(a2) if v==1]

# lists of indices where 1 exists in each list...
print(a1_one_locations)
print(a2_one_locations)

n_samples = 6 # total desired

# 40% from a1, remainder from a2
a1_samples = int(n_samples * 0.4)
a2_samples = n_samples - a1_samples
a1_picks = random.sample(a1_one_locations, a1_samples)
a2_picks = random.sample(a2_one_locations, a2_samples)

# print results
print('indices from a1: ', a1_picks)
print('indices from a2: ', a2_picks)

输出：

[0, 4, 6, 8, 9, 10, 11, 12, 16, 17, 19, 21, 23, 25]
[2, 4, 6, 10, 12, 13, 15, 18, 20, 24]
indices from a1:  [6, 21]
indices from a2:  [10, 15, 4, 20]

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根据您的描述推断，是否要避免从不同行中的相同索引位置拾取位？（不清楚你所说的重叠和上面没有100b是什么意思…）所以使用“random.sample（）”来选择100个索引位置，然后对于每个绘图，使用加权分布来选择要从中选择的行。我明白了，所以你创建了随机2D索引。。然后把这些碎片捡起来。。。对的顺便说一句，我只需要挑一个

import random
a1= '10001010111110001101010101'
a2= '00101010001011010010100010'
a1 = [int(t) for t in a1]
a2 = [int(t) for t in a2]
a1_one_locations= [idx for idx, v in enumerate(a1) if v==1]
a2_one_locations= [idx for idx, v in enumerate(a2) if v==1]

# lists of indices where 1 exists in each list...
print(a1_one_locations)
print(a2_one_locations)

n_samples = 6 # total desired

# 40% from a1, remainder from a2
a1_samples = int(n_samples * 0.4)
a2_samples = n_samples - a1_samples
a1_picks = random.sample(a1_one_locations, a1_samples)
a2_picks = random.sample(a2_one_locations, a2_samples)

# print results
print('indices from a1: ', a1_picks)
print('indices from a2: ', a2_picks)

[0, 4, 6, 8, 9, 10, 11, 12, 16, 17, 19, 21, 23, 25]
[2, 4, 6, 10, 12, 13, 15, 18, 20, 24]
indices from a1:  [6, 21]
indices from a2:  [10, 15, 4, 20]