Python IF查询

我想做一个计算入学费用的程序。。我已经设法做到了，除了一部分需要两个成年人和三个孩子，那么费用是15美元。这是否应该使用if语句来完成，我将如何完成

import math 

loop = 1
choice = 0
while loop == 1:

    print "Welcome"

    print "What would you like to do?:"
    print " "
    print "1) Calculate entrance cost"

    print "2) Leave swimming centre"
    print " "

    choice = int(raw_input("Choose your option: ").strip())
    if choice == 1:
        add1 = input("Adults: ")
        add2 = input("Concessions: ")
        add3 = input("Children: ")
        print add1, "+", add2, "+", add3, "answer=", add1 *5 + add2 *3 + add3 *2   
    elif choice == 2:
        loop = 0

---

感谢您的帮助，我们将不胜感激

对于一个特殊情况，如果你有两个成年人，三个孩子，你应该放置一个if语句。否则你应该正常计算。我已经评论了发生这种特殊情况的领域

本准则还假设特殊情况不影响优惠价格

import math 

loop = 1
choice = 0
while loop == 1:

    print "Welcome"

    print "What would you like to do?:"
    print " "
    print "1) Calculate entrance cost"

    print "2) Leave swimming centre"
    print " "

    choice = int(raw_input("Choose your option: ").strip())

    if choice == 1:
        add1 = input("Adults: ")
        add2 = input("Concessions: ")
        add3 = input("Children: ")

        cost = 0

        # special case for 2 adults, 3 children
        if add1 == 2 and add3 == 3:
            cost += 15
        else:
            cost += add1*5 + add3*2

        # concession cost
        cost += add2 *3

        print add1, "+", add2, "+", add3, "answer=", cost

    elif choice == 2:
        loop = 0

---

不要使用循环变量，只需使用

而True:

然后在希望循环结束时使用

中断

。如果add1==2和add3==3，则使用类似

的方法：打印“$15”

。然后将print语句放在

else:

之后。现在可以了，不过我更喜欢您更改的代码部分。

import math 

choice = 0
while True:

    print """
       Welcome

       What would you like to do?:

       1)Calculate entrance cost
       2) Leave swimming centre
      """

   choice = int(raw_input("Choose your option: ").strip())
   if choice == 1:
       add1 = input("Adults: ")
       add2 = input("Concessions: ")
       add3 = input("Children: ")
       print add1, "+", add2, "+", add3, "answer=", add1 *5 + add2 *3 + add3 *2   
   elif choice == 2:
       break