R：如果向量构成列表的一部分，如何从向量中获取元素？

我有两份清单：

myList1 <- list(c("","VNW","SPEC","N","BW" ), c("","WW","N","SPEC","ADJ"),c( "","WW","N"), c("","WW","N"), c("","ADJ","N","WW"), c( "","ADJ","N"))

myList2 <- list(c( "","125141","44","4945","3"), c("","114146","77","19","3"), c("","4359","695"), c("","1372","623"), c("","209","71","1"), c( "","33","3"))

myList1你可以试试

MyFinalValues <- mapply(function(x,i) x[i],x=myList2, i=MyNIndices)
if(is.list(MyNIndices)) MyFinalValues=list(MyFinalValues)

MyFinalValues您可以试试

MyFinalValues <- mapply(function(x,i) x[i],x=myList2, i=MyNIndices)
if(is.list(MyNIndices)) MyFinalValues=list(MyFinalValues)

MyFinalValue在tidyverse中，您可以

library(purrr)
map2(myList2,MyNIndices, `[[`)

或者，如果你想要一个数值向量

map2_chr(myList2,MyNIndices, `[[`) %>% 
    as.numeric()

在tidyverse你可以

library(purrr)
map2(myList2,MyNIndices, `[[`)

或者，如果你想要一个数值向量

map2_chr(myList2,MyNIndices, `[[`) %>% 
    as.numeric()

map2_chr(myList2,MyNIndices, `[[`) %>% 
    as.numeric()