SQL-GROUPBY-合并列';将值放在一行中?
(在SSMS2016工作)我的表格如下:SQL-GROUPBY-合并列';将值放在一行中?,sql,sql-server,sql-server-2016,ssms-2016,Sql,Sql Server,Sql Server 2016,Ssms 2016,(在SSMS2016工作)我的表格如下: | ORDER_NUMBER | ITEM_CAT| ORDER_QTY | UNALLOCATED| |--------------|---------|-----------|------------| | 1 | FLAT | 2 | 1 | | 1 | HANG | 1 | 1 | | 1 | SHOE
| ORDER_NUMBER | ITEM_CAT| ORDER_QTY | UNALLOCATED|
|--------------|---------|-----------|------------|
| 1 | FLAT | 2 | 1 |
| 1 | HANG | 1 | 1 |
| 1 | SHOE | 2 | 1 |
| 2 | FLAT | 1 | 1 |
| 2 | FLAT | 1 | 1 |
| 3 | SHOE | 1 | 1 |
| 3 | SHOE | 1 | 1 |
| 3 | SHOE | 1 | 1 |
| 4 | FLAT | 1 | 1 |
| 4 | SHOE | 1 | 1 |
| 4 | FLAT | 1 | 1 |
| 4 | SHOE | 1 | 1 |
如果我这样做
SELECT ORDER_NUMBER, ITEM_CAT, SUM(ORDER_QTY) AS 'ORDER_QTY', SUM(UNALLOCATED) AS 'UNALLOCATED'
FROM TABLEA
GROUP BY ORDER_NUMBER, ITEM_CAT
我得到以下信息:
| ORDER_NUMBER | ITEM_CAT| ORDER_QTY | UNALLOCATED|
|--------------|---------|-----------|------------|
| 1 | FLAT | 2 | 1 |
| 1 | HANG | 1 | 1 |
| 1 | SHOE | 2 | 1 |
| 2 | FLAT | 2 | 2 |
| 3 | SHOE | 3 | 3 |
| 4 | FLAT | 2 | 2 |
| 4 | SHOE | 2 | 2 |
理想情况下,我希望每个订单号只获得一行,并在同一行中列出唯一的ITEM_CAT值,如下所示:
| ORDER_NUMBER | ITEM_CAT | ORDER_QTY | UNALLOCATED|
|--------------|----------------------|-----------|------------|
| 1 | FLAT / HANG / SHOE | 5 | 3 |
| 2 | FLAT | 2 | 2 |
| 3 | SHOE | 3 | 3 |
| 4 | FLAT / SHOE | 4 | 4 |
这是否容易做到
谢谢。如果您使用的是SQL Server 2016,您可以使用
string\u agg()
:
如果您使用的是SQL Server 2016,则可以使用
string\u agg()
:
虽然这可能是某个问题的重复,但它不是建议问题的重复。自SQL Server 2005以来,SQL Server的功能已发生更改,导致该解决方案过时。尽管这可能是某些问题的重复,但它不是建议的问题的重复。自SQL Server 2005以来,SQL Server的功能发生了变化,使该解决方案过时。非常感谢。我认为string_agg()是在2017年添加的(或者可能是2016年的更高版本),所以很遗憾我不能使用它。然而,它确实让我找到了“XML路径的东西”,经过一番尝试和错误,我终于得到了我所需要的东西。非常感谢。我认为string_agg()是在2017年添加的(或者可能是2016年的更高版本),所以很遗憾我不能使用它。然而,它确实让我找到了“XML路径的东西”,经过一点尝试和错误,我成功地得到了我所需要的东西。
SELECT ORDER_NUMBER,
STRING_AGG(ITEM_CAT, ' / ') as ITEM_CATS,
SUM(ORDER_QTY) AS ORDER_QTY,
SUM(UNALLOCATED) AS UNALLOCATED
FROM (SELECT ORDER_NUMBER, ITEM_CAT, SUM(ORDER_QTY) AS ORDER_QTY,
SUM(UNALLOCATED) AS UNALLOCATED
FROM TABLEA
GROUP BY ORDER_NUMBER, ITEM_CAT
) a
GROUP BY ORDER_NUMBER;