Oracle SQL-重新排列以前的数据透视表

我有这张桌子：

+-----------+---------------+------------------+
|    ID     |     Rule 1    | Rule 2  | Rule 3 |
+-----------+---------------+------------------+
| ID001     | PASSED        | FAILED  | PASSED |
| ID002     | FAILED        | FAILED  | FAILED |
| ID003     | FAILED        | PASSED  | PASSED |
+-----------+---------------+---------+--------+

我想将它转换为在每个规则下都有失败的ID

预期结果如下：

+-----------+---------+--------+
| Rule 1    | Rule 2  | Rule 3 |
+-----------+---------+--------+
| -         | ID001   | -      |
| ID002     | ID002   | ID002  |
| ID003     | -       | -      |
+-----------+---------+--------+

---

如何实现这一点？

您可以使用条件语句：

SELECT CASE WHEN Rule1 = 'FAILED' THEN ID END AS Rule1,
       CASE WHEN Rule2 = 'FAILED' THEN ID END AS Rule2,
       CASE WHEN Rule3 = 'FAILED' THEN ID END AS Rule3
  FROM t