Sqlite 尝试更新单行中的多个字段,但创建重复行

Sqlite 尝试更新单行中的多个字段,但创建重复行,sqlite,Sqlite,编辑: 我在Salesforce Marketing Cloud中使用SQL查询,这意味着我仅限于执行“Select”语句来覆盖表[Distribution]。我正在尝试执行以下操作: select * from [Subscribers] A inner join [Master Table] B on A.MemberID = B.MemberID 这部分按预期工作 接下来我有两个字段,Reward1和Reward2,每个字段对应于[Offers]中的特定RewardCode。因此,我尝试

编辑:

我在Salesforce Marketing Cloud中使用SQL查询,这意味着我仅限于执行“Select”语句来覆盖表[Distribution]。我正在尝试执行以下操作:

select * from [Subscribers] A
inner join [Master Table] B on A.MemberID = B.MemberID
这部分按预期工作

接下来我有两个字段,Reward1和Reward2,每个字段对应于[Offers]中的特定RewardCode。因此,我尝试(我认为)在MemberID上与[Subscribers]和[Offices]左连接,其中RewardCode=111111,与[Subscribers]和[Offices]左连接,其中RewardCode=2222。然而,这就是我似乎在创建重复记录的地方

模式的示例如下所示:

主成员表

memberID | email | fname | lname
1111 | 1111@email.com | One | Name
2222 | 2222@email.com | Two | Name
3333 | 3333@email.com | Three | Name
4444 | 4444@email.com | Four | Name
memberID | rewardcode
1111 | 111111
1111 | 111111
1111 | 111111
2222 | 111111
2222 | 222222
2222 | 222222
3333 | 222222
3333 | 111111
4444 | 222222
4444 | 333333
4444 | 222222
订户

memberID | status | subscriberkey
1111 | active | 1111@email.com
2222 | active | 2222@email.com
3333 | active | 3333@email.com
4444 | active | 4444@email.com
主奖励表

memberID | email | fname | lname
1111 | 1111@email.com | One | Name
2222 | 2222@email.com | Two | Name
3333 | 3333@email.com | Three | Name
4444 | 4444@email.com | Four | Name
memberID | rewardcode
1111 | 111111
1111 | 111111
1111 | 111111
2222 | 111111
2222 | 222222
2222 | 222222
3333 | 222222
3333 | 111111
4444 | 222222
4444 | 333333
4444 | 222222
理想情况下,生成的表格如下所示:

[distribution]
subscriberkey | memberId | status| reward1 | reward2
1111@email.com| 1111 | active | TRUE | FALSE
2222@email.com| 2222 | active TRUE | TRUE
3333@email.com| 3333 | active TRUE | TRUE
4444@email.com| 4444 | active FALSE | TRUE
完整查询:

SELECT A.SubscriberKey AS SubscriberKey, A.EmailAddress AS EmailAddress,
A.MemberID AS MemberId, A.Status AS Status,
A.Decile AS Decile, A.Segment AS Segment, M.Firstname AS FirstName,
M.LastName AS LastName, M.Points AS PointsAvailable,
M.Experience AS Experience,
    CASE
        WHEN M.[Preferred Delivery Method for Offers] = 2 THEN 'SMS'
        ELSE 'Email'
    END AS PreferredDeliveryOffers,
    CASE
        WHEN M.[Preferred Delivery Method for Non-Offers] = 2 THEN 'SMS'
        ELSE 'Email'
    END AS PreferredDeliveryNonOffers,
    CASE
        WHEN R.MemberRewardBarcode IS NOT NULL AND
        R.[Member ID] = M.MemberId AND
        R.MemberRewardBarcode = 1111111 THEN 'Reward15'
        ELSE ''
    END AS Reward15,
    CASE
        WHEN B.MemberRewardBarcode IS NOT NULL AND
        B.[Member ID] = M.MemberId AND
        B.MemberRewardBarcode = 2222222 THEN 'RewardBDay'
        ELSE ''
    END AS RewardBDay
FROM Subscribers A
INNER JOIN [Master Member Table] M
    ON A.MemberID = M.MemberId
LEFT JOIN (
    SELECT DISTINCT MemberRewardBarcode, [Member ID]
    FROM [master rewards table] R
    WHERE R.MemberRewardBarcode = 1111111 AND
    R.CancelTimestamp IS NULL AND
    R.ExpireTimestamp IS NULL AND
    R.RedeemTimestamp IS NULL
  ) R ON A.MemberID = R.[Member ID]
LEFT JOIN (
    SELECT DISTINCT MemberRewardBarcode, [Member ID]
    FROM [master rewards table] R
    WHERE R.MemberRewardBarcode = 2222222 AND
    R.CancelTimestamp IS NULL AND
    R.ExpireTimestamp IS NULL AND
    R.RedeemTimestamp IS NULL
    GROUP BY MemberRewardBarcode, [Member ID]
  ) B ON A.MemberID = R.[Member ID]

您应该能够使用条件聚合解决此问题:

此查询使用非常常见的SQL语法(聚合和
CASE
),据我在您提供的文档中所见,Salesforce Marketing Cloud应该支持这些语法

返回:

subscriberkey | memberID | status | reward1 | reward2 :------------- | -------: | :----- | ------: | ------: 1111@email.com | 1111 | active | 1 | null 2222@email.com | 2222 | active | 1 | 1 3333@email.com | 3333 | active | 1 | 1 4444@email.com | 4444 | active | null | null subscriberkey | memberID | status | reward1 | reward2 :------------- | -------: | :----- | ------: | ------: 1111@email.com| 1111 |活动| 1 |空 2222@email.com| 2222 |主动| 1 | 1 3333@email.com| 3333 |主动| 1 | 1 4444@email.com| 4444 |活动|空|空