C++ c++;,linux,如何解释'stat64'中文件的模式?

C++ c++;,linux,如何解释'stat64'中文件的模式?,c++,linux,C++,Linux,在那里,我试图确定一个文件是文件夹还是文件夹中的文件 struct dirent **name_list; int n, i; n = scandir(".", &name_list, NULL, alphasort); for(i=0;i<n;i++){ struct stat64 stat_list stat64(name_list[i]->d_name, &stat_list); cout << stat_list.st_mod

在那里,我试图确定一个文件是文件夹还是文件夹中的文件

struct dirent **name_list;
int n, i;    
n = scandir(".", &name_list, NULL, alphasort);

for(i=0;i<n;i++){
  struct stat64 stat_list
  stat64(name_list[i]->d_name, &stat_list);
  cout << stat_list.st_mode << endl;
}
struct dirent**name\u列表;
int n,i;
n=scandir(“.”,&name\u list,NULL,alphasort);
对于(i=0;id\u名称和统计列表);
我会说:)

我会说:)


stat
man
页面有一个表,其中列出了每个标志的含义

       S_IFMT     0170000   bit mask for the file type bit fields
       S_IFSOCK   0140000   socket
       S_IFLNK    0120000   symbolic link
       S_IFREG    0100000   regular file
       S_IFBLK    0060000   block device
       S_IFDIR    0040000   directory
       S_IFCHR    0020000   character device
       S_IFIFO    0010000   FIFO
       S_ISUID    0004000   set UID bit
       S_ISGID    0002000   set-group-ID bit (see below)
       S_ISVTX    0001000   sticky bit (see below)
       S_IRWXU    00700     mask for file owner permissions
       S_IRUSR    00400     owner has read permission
       S_IWUSR    00200     owner has write permission
       S_IXUSR    00100     owner has execute permission
       S_IRWXG    00070     mask for group permissions
       S_IRGRP    00040     group has read permission

       S_IWGRP    00020     group has write permission
       S_IXGRP    00010     group has execute permission
       S_IRWXO    00007     mask for permissions for others (not in group)
       S_IROTH    00004     others have read permission
       S_IWOTH    00002     others have write permission
       S_IXOTH    00001     others have execute permission
问题中模式的数字表示形式输出为十进制,但是如果将其转换为八进制,则位字段更有意义


文件的
33188
转换为
0o100644
,这意味着它是一个常规文件,所有者只读/写,组/其他只读<目录的code>16877
转换为
0o40755
,这意味着它是一个具有所有所有者权限的目录,并且对组和其他对象具有读取/执行权限。

用于
stat
man
页面有一个每个标志的含义表

       S_IFMT     0170000   bit mask for the file type bit fields
       S_IFSOCK   0140000   socket
       S_IFLNK    0120000   symbolic link
       S_IFREG    0100000   regular file
       S_IFBLK    0060000   block device
       S_IFDIR    0040000   directory
       S_IFCHR    0020000   character device
       S_IFIFO    0010000   FIFO
       S_ISUID    0004000   set UID bit
       S_ISGID    0002000   set-group-ID bit (see below)
       S_ISVTX    0001000   sticky bit (see below)
       S_IRWXU    00700     mask for file owner permissions
       S_IRUSR    00400     owner has read permission
       S_IWUSR    00200     owner has write permission
       S_IXUSR    00100     owner has execute permission
       S_IRWXG    00070     mask for group permissions
       S_IRGRP    00040     group has read permission

       S_IWGRP    00020     group has write permission
       S_IXGRP    00010     group has execute permission
       S_IRWXO    00007     mask for permissions for others (not in group)
       S_IROTH    00004     others have read permission
       S_IWOTH    00002     others have write permission
       S_IXOTH    00001     others have execute permission
问题中模式的数字表示形式输出为十进制,但是如果将其转换为八进制,则位字段更有意义


文件的
33188
转换为
0o100644
,这意味着它是一个常规文件,所有者只读/写,组/其他只读<代码>16877用于将目录转换为
0o40755
,这意味着它是一个具有所有所有者权限的目录,并且对组和其他文件具有读取/执行权限。

是的,很抱歉,我不认为使用“man”来表示这一点。。。几乎每次当我使用man+函数时,我都一无所获。。。但好吧,我同意在这种情况下,告诉我RTFM是公平的。如果你在
man
方面运气不好,我建议你使用一个好的搜索引擎,比如说,是的,我很抱歉我不认为用“man”来做这个。。。几乎每次当我使用man+函数时,我都一无所获。。。但是,好吧,我同意在这种情况下,告诉我RTFM是公平的。如果你在
man
方面运气不好,我建议你使用一个好的搜索引擎,比如,我更新了我的答案,并补充了一些关于标志如何工作的解释。我更新了我的答案,补充了一些关于标志如何工作的解释。