C++ (C+;+;)处理链表时,进程返回-1073741819(0xC0000005),但算法有效

C++ (C+;+;)处理链表时,进程返回-1073741819(0xC0000005),但算法有效,c++,list,C++,List,此程序的目标是从列表中删除大于以下元素的任何元素。我已经设法让这个程序执行这个任务,但是它在执行此操作后立即崩溃,并且随后不打印列表,输出一个0xC0000005错误代码 #include <iostream> using namespace std; class List{ struct node{ int data; node* next; }; typedef struct node* nodePtr; nodeP

此程序的目标是从列表中删除大于以下元素的任何元素。我已经设法让这个程序执行这个任务,但是它在执行此操作后立即崩溃,并且随后不打印列表,输出一个0xC0000005错误代码

#include <iostream>
using namespace std;
class List{
    struct node{
        int data;
        node* next;
    };
    typedef struct node* nodePtr;
    nodePtr head;
    nodePtr curr;
    nodePtr temp;

public:
    List()
    {
        head=NULL;
        curr=NULL;
        temp=NULL;
    }
    void AddNode(int addData)
    {
        nodePtr n = new node;
        n->next = NULL;
        n->data = addData;
        if(head != NULL) {
            curr = head;
            while(curr->next != NULL) {
                curr = curr->next;
            }
            curr->next = n;
        }
        else
        {
            head = n;
        }
    };
    void DeleteNode(int delData)
    {
        nodePtr delPtr = NULL;
        temp = head;
        curr = head;
        while(curr != NULL && curr->data != delData) {
            temp = curr;
            curr = curr->next;
        }
        if(curr == NULL) {
            cout << delData << " is not in the list" << endl;
            delete delPtr;
        }
        else {
            delPtr = curr;
            curr = curr->next;
            temp->next = curr;
            if(delPtr == head) {
                head = head->next;
                temp = NULL;
            }
            delete delPtr;
            cout << delData << " was removed from the list" << endl;
        }
    };
    void PrintList()
    {   cout << "List: " << endl;
        curr = head;
        while (curr != NULL) {
            cout << curr->data << endl;
            curr = curr->next;
        }
    }
    void toss()
    {
        curr = head;
        while (curr != NULL) {

            if(curr->data>curr->next->data){
                    DeleteNode(curr->data);
                    curr = head;
            }
            else curr = curr->next;
            if(curr == NULL) break;
        }

    }
};
int main() {
    List list;
    int i;
    cout << "Input list values, stop input by inputting 0: " << endl;
    cin >> i;
    while(i != 0){
        list.AddNode(i);
        cin >> i; // 18 9 3 4 0 
}
    list.PrintList(); // 18 9 3 4
    list.toss(); // tosses 18 and 9
    list.PrintList(); // should output 3 4 
};

如果您对此问题有任何意见或帮助,我们将不胜感激,谢谢

当它到达列表中的最后一个节点时,aka
curr->next
等于null,您试图访问
curr->next->data
,但next为null。将if语句更改为:

    while (curr != NULL) {

        if(curr->next != NULL && curr->data > curr->next->data){
                DeleteNode(curr->data);
                curr = head;
        }
        else curr = curr->next;
        if(curr == NULL) break;
    }
或者类似的东西。您还可以在while循环的条件中检查这一点


所以基本上,在访问布局良好的问题之前,您必须确保
curr->next
不为空。让我们看看我们能做些什么来帮助。
如果(curr->data>curr->next->data)
可疑
curr
已经过测试,并且被认为是良好的,但是未选中
curr->next
。列表中的最后一项将爆炸,因为没有
next
无关:
if(curr==NULL)中断是多余的。循环条件可以为您执行此操作。@user4581301我将其更改为while(curr!=NULL&&curr->next!=NULL),现在它似乎可以工作了,非常感谢!!无关:用于简化
DeleteNode
    while (curr != NULL) {

        if(curr->next != NULL && curr->data > curr->next->data){
                DeleteNode(curr->data);
                curr = head;
        }
        else curr = curr->next;
        if(curr == NULL) break;
    }