C# 使用LINQ Group By返回新元素
我有以下代码,弄糊涂了: 我有一个查询,返回一组被标识为重复的记录,然后我想为每个记录创建一个XElement。我想这应该在一个查询中完成,但我现在迷路了C# 使用LINQ Group By返回新元素,c#,linq,.net-3.5,c#-3.0,linq-to-xml,C#,Linq,.net 3.5,C# 3.0,Linq To Xml,我有以下代码,弄糊涂了: 我有一个查询,返回一组被标识为重复的记录,然后我想为每个记录创建一个XElement。我想这应该在一个查询中完成,但我现在迷路了 var f = (from x in MyDocument.Descendants("RECORD") where itemsThatWasDuplicated.Contains((int)x.Element("DOCUMENTID"))
var f = (from x in MyDocument.Descendants("RECORD")
where itemsThatWasDuplicated.Contains((int)x.Element("DOCUMENTID"))
group x by x.Element("DOCUMENTID").Value into g
let item = g.Skip(1) //Ignore first as that is the valid one
select item
);
var errorQuery = (from x in f
let sequenceNumber = x.Element("DOCUMENTID").Value
let detail = "Sequence number " + sequenceNumber + " was read more than once"
select new XElement("ERROR",
new XElement("DATETIME", time),
new XElement("DETAIL", detail),
new XAttribute("TYPE", "DUP"),
new XElement("ID", x.Element("ID").Value)
)
);
x、 每次迭代,是元素的序列(不包括第一个元素)。我怀疑你想要:
from grp in f
from x in grp
let sequenceNumber = x.Element("DOCUMENTID").Value
//...
尽管您也可以根据需要在投影中显示组键,但可以进一步简化:
var f = (from x in MyDocument.Descendants("RECORD")
where itemsThatWasDuplicated.Contains((int)x.Element("DOCUMENTID"))
group x by x.Element("DOCUMENTID").Value);
var errorQuery = (from grp in f
from x in grp.Skip(1)
let detail = "Sequence number " + grp.Key + " was read more than once"
//...
我已经成功地编译了它,并且似乎可以工作,但是可能需要一些性能调整,或者我正在做一些低效的事情。你觉得怎么样
errorQuery = MyDocument.Descendants("RECORD")
.Where(x => itemsThatWasDuplicated.Contains((int)x.Element("DOCUMENTID")))
.GroupBy(a => a.Element("DOCUMENTID"), (innerID, values) => values.OrderBy(b => b.Element("ID").Value))
.Skip(1)
.SelectMany(p => p)
.Select(item => new XElement("ERROR",
new XElement("DATETIME", time),
new XElement("DETAIL", "Sequence number " + item.Element("DOCUMENTID").Value + " was read more than once"),
new XAttribute("TYPE", "DUP"),
new XElement("ID", item.Element("ID").Value)
));