关于django日历错误

我有一些错误：我该怎么做？为什么我不能导入日历？ 我正在使用导入日历。对吗？ 这就是错误：

Request Method: GET
Request URL: http://articles/month
Django Version: 1.6.2
Exception Type: TypeError 
Exception Value: month() takes at least 3 arguments (1 given)
Python Executable: /usr/bin/python

这是一个管理错误：

Request Method:     GET
Request URL:    http://dev1.so2.co.jp/ihttest/ihttcs_test/admin/auth/user/
Django Version:     1.6.2
Exception Type:     ViewDoesNotExist
Exception Value:    
Could not import tcsarticle.views.calendar. View is not callable.

这是my views.py：

def month(request, year, month, change=None):
    year, month = int(year), int(month)
    if change in ("next", "prev"):
        now, mdelta = date(year, month, 15), timedelta(days=31)
        if change == "next":   mod = mdelta
        elif change == "prev": mod = -mdelta
        year, month = (now+mod).timetuple()[:2]
    article = calendar.Calendar()

    month_days = tcsarticle.itermonthdays(year, month)
    nyear, nmonth, nday = time.localtime()[:3]
    lst = [[]]
    week = 0

    for day in month_days:
        entries = current = False   # are there entries for this day; current day?
        if day:
            entries = User.objects.filter(date__year=year, date__month=month, date__day=day)
            if day == nday and year == nyear and month == nmonth:
                current = True
        lst[week].append((day, entries, current))
        if len(lst[week]) == 7:
            lst.append([])
            week += 1
    return render_to_response("month.html", dict(year=year, month=month,user=request.user,
month_days=lst, mname=mnames[month-1]))

这是URL.py：

url(r"^month/(\d+)/(\d+)/(prev|next)/$", "article.views.month"),
url(r"^month/(\d+)/(\d+)/$", "article.views.month"),
url(r"^month/$", "article.views.month"),

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将URL.py更改为以下代码。你也应该仔细阅读

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URL.py文件中不能有最后一行，因为它引用的是view article.views.month，它至少需要两个参数month和year，而该URL不会向其中传递任何参数。

与views.py文件在同一目录中是否有calendar.py？不，没有，我不知道calendar.py！！你的URL.py文件是什么样子的？好的，这是URL.py:urlr^month/\d+/\d+/prev | next/$，article.views.month，urlr^month/\d+/\d+/$，article.views.month，urlr^month/$，article.views.month，这是答案吗？如果是这样的话，你能这样标记吗？请将我的答案标记为你问题的答案。

url(r"^month/(?P<year>\d+)/(?P<month>\d+)/(prev|next)/$", "article.views.month"),
url(r"^month/(?P<year>\d+)/(?P<month>\d+)/$", "article.views.month"),