如何在Android Java方法中形成更好的布尔值

我有一个方法，一天内被调用多次

public void dayUpdater() {
    Date now = new Date();
    SimpleDateFormat numDate = new SimpleDateFormat("EEEE");

    String[] Days = {"Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"};
    String day = numDate.format(now);

    if (day.equals(Days[0])) {
        Toast.makeText(getApplicationContext(), "Total for " + numDate.format(now)
                + " is " + 5000, Toast.LENGTH_LONG).show();
    if (day.equals(Days[1])) Toast.makeText(getApplicationContext(), "Total for " + numDate.format(now)
                + " is " + 5000, Toast.LENGTH_LONG).show();
    if (day.equals(Days[2])) Toast.makeText(getApplicationContext(), "Total for " + numDate.format(now)
                + " is " + 4000, Toast.LENGTH_LONG).show();
    if (day.equals(Days[3])) Toast.makeText(getApplicationContext(), "Total for " + numDate.format(now)
                + " is " + 3000, Toast.LENGTH_LONG).show();
    if (day.equals(Days[4])) Toast.makeText(getApplicationContext(), "Total for " + numDate.format(now)
                + " is " + 2000, Toast.LENGTH_LONG).show();
    if (day.equals(Days[5])) Toast.makeText(getApplicationContext(), "Total for " + numDate.format(now)
                + " is " + 1000, Toast.LENGTH_LONG).show();
    if (day.equals(Days[6])) Toast.makeText(getApplicationContext(), "Total for " + numDate.format(now)
                + " is " + 1000, Toast.LENGTH_LONG).show();

}

现在每天只调用1个if语句。我已经创建了一个名为xbool的bool来帮助每天调用一次我的方法。另外，要调用的方法如下所示

private boolean xbool = true;

private void reStartDay() {
    saveAllContents();
    clearAllEntries();
}

如果xbool为false，则调用我们的方法，然后将其转换为true。如果这是真的，我们什么也不做。下面是应用于每个if语句的工作示例

if (day.equals(Days[0])) {
        Toast.makeText(getApplicationContext(), "Total for " + numDate.format(now)
                + " is " + 5000, Toast.LENGTH_LONG).show();
        if (xbool == false) {
            reStartDay();
            xbool = true;
        }
    }

我的问题是第二天一到。i、 e.在这种情况下，另一个if语句从上述代码到：

if (day.equals(Days[1])) {
        Toast.makeText(getApplicationContext(), "Total for " + numDate.format(now)
                + " is " + 5000, Toast.LENGTH_LONG).show();
        if (xbool == false) {
            reStartDay();
            xbool = true;
        }
    }

其中，天现在等于天[1]，而不是天[0]。问题是我的xbool是真的。因此，在新的一天不会有重新开始的电话，因为xbool不是假的。 我决定将dayUpdater中的每个if语句切换到相反的位置。看起来是这样的：

if (day.equals(Days[0])) { 
    if (xbool == false){
        reStartDay();
        xbool = true;
    }
}
if (day.equals(Days[2])) { 
    if (xbool == true){
        reStartDay();
        xbool = false;
    }
}

星期三检查false并将xbool变为true。等等。。你明白了

一旦我到了星期天，尽管它不符合星期一的期望，但星期天会检查xbool是否为false并将其更改为true

但周一预计xbool为假，因此它可以在周一调用reStartDay。 我需要关于做什么的建议。或者改变什么。请

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我从来都不擅长布尔运算，所以我知道无论我得到什么答案/建议，我都会学到一些东西。

根据您的代码，看起来您希望每天只执行一次特定代码，尽管该方法每天运行多次

为了实现同样的目标，您可以这样做

像这样声明一个实例变量

private String currentDay = null;

public void dayUpdater() {
    Date now = new Date();
    SimpleDateFormat numDate = new SimpleDateFormat("EEEE");
    String[] Days = {"Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"};
    String day = numDate.format(now);
    if (!day.equals(currentDay)) {
        Toast.makeText(getApplicationContext(), "Total for " + day
                + " is " + 5000, Toast.LENGTH_LONG).show();
        reStartDay();
        currentDay = day;
    }
}

在你的dayUpdater方法中，不要写那么多的if，如果你只是这样写会怎么样

private String currentDay = null;

public void dayUpdater() {
    Date now = new Date();
    SimpleDateFormat numDate = new SimpleDateFormat("EEEE");
    String[] Days = {"Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"};
    String day = numDate.format(now);
    if (!day.equals(currentDay)) {
        Toast.makeText(getApplicationContext(), "Total for " + day
                + " is " + 5000, Toast.LENGTH_LONG).show();
        reStartDay();
        currentDay = day;
    }
}

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希望这对您有用。

您可以去掉字符串[]天={Monday…声明为wellBeyond:每次当你有一个数组或列表，并且你开始手动放置这样的索引时…你做了一些错误的事情。基本主题是在循环中迭代这样的结构，并避免像你那样使用它们。你看，你也可以编写字符串day1=…；字符串day2=。。..您的代码不会从使用数组中获得任何好处。