扫描文件时发生java.util.NoSuchElementException
我正在从文件中读取并将所有内容保存到其中。整个程序运行良好,但我没有阅读文件的最后一行,当我尝试这样做时,事情变得很奇怪,文件的最后一行是“文件的结尾”。我尝试将它保存为字符串,但它不起作用,那是在我收到错误消息时,但现在我从代码中删除了所有内容,它没有完全运行程序,它最后输出的是工作是,这是我在main中的最后一个for循环 这是我的密码:扫描文件时发生java.util.NoSuchElementException,java,Java,我正在从文件中读取并将所有内容保存到其中。整个程序运行良好,但我没有阅读文件的最后一行,当我尝试这样做时,事情变得很奇怪,文件的最后一行是“文件的结尾”。我尝试将它保存为字符串,但它不起作用,那是在我收到错误消息时,但现在我从代码中删除了所有内容,它没有完全运行程序,它最后输出的是工作是,这是我在main中的最后一个for循环 这是我的密码: import java.io.*; import java.util.Scanner; public class hurry2 { publi
import java.io.*;
import java.util.Scanner;
public class hurry2 {
public static void main (String [] args) throws IOException
{
File candidates = new File("cipcs115.txt");
Scanner scan = new Scanner(candidates);
Scanner user = new Scanner(System.in);
String state = scan.next();
int numOfCan = scan.nextInt();
String what = scan.nextLine();
String stateWi ;
String stateAl ;
String stateDe ;
int numOfCanWi ;
int numOfCanAl ;
int numOfCanDe ;
Candidate [] candiIl ;
Candidate [] candiWi;
Candidate [] candiAl ;
Candidate [] candiDe;
hurry2 cill = new hurry2();
candiIl = new Candidate[numOfCan];
for ( int i=0; i<numOfCan; i++)
{
String three = scan.next();
String four = scan.next();
String five = scan.next();
int six = scan.nextInt();
double seven = scan.nextDouble();
String eight = scan.nextLine();
Candidate night = new Candidate (three,four,five,six,seven,eight);
candiIl [i] = night ;
System.out.println(night.getName() + " " + night.getMotto());
}
stateWi = scan.next();
numOfCanWi = scan.nextInt();
candiWi = new Candidate[numOfCanWi];
for ( int i=0; i<numOfCanWi; i++)
{
String three = scan.next();
String four = scan.next();
String five = scan.next();
int six = scan.nextInt();
double seven = scan.nextDouble();
String eight = scan.nextLine();
Candidate night = new Candidate (three,four,five,six,seven,eight);
candiWi [i] = night ;
System.out.println(night.getName() + " " + night.getMotto());
}
stateAl = scan.next();
numOfCanAl = scan.nextInt();
candiAl = new Candidate[numOfCanAl];
for ( int i=0; i<numOfCanAl; i++)
{
String three = scan.next();
String four = scan.next();
String five = scan.next();
int six = scan.nextInt();
double seven = scan.nextDouble();
String eight = scan.nextLine();
Candidate night = new Candidate (three,four,five,six,seven,eight);
candiAl [i] = night ;
System.out.println(night.getName() + " " + night.getMotto());
}
stateDe = scan.next();
numOfCanDe = scan.nextInt();
candiDe = new Candidate[numOfCanDe];
for ( int i=0; i<numOfCanAl; i++)
{
String three = scan.next();
String four = scan.next();
String five = scan.next();
int six = scan.nextInt();
double seven = scan.nextDouble();
String eight = scan.nextLine();
Candidate night = new Candidate (three,four,five,six,seven,eight);
candiDe [i] = night ;
System.out.println(night.getName() + " " + night.getMotto());
System.out.println("yes");
}
System.out.println(" what would you like to do? >");
String option = user.next();
switch (option)
{
case "m":
case "M":
cill.menu(candiIl);
break;
}
scan.close();
}
public static void menu(Candidate [] rod)
{
hurry2 cill1 = new hurry2();
Scanner menus = new Scanner(System.in);
System.out.print( "What would you like to do next >");
String option1 = menus.next() ;
switch (option1)
{
case "l" :
case "L" :
cill1.listall(rod);
break ;
}
return ;
}
public static void listall(Candidate [] yes)
{
int numOfCan = 3;
for (int s =0; s<numOfCan;s++)
System.out.println(yes[s].getName() + yes[s].getParty() + yes[s].getMotto());
return ;
}
}
似乎您正在尝试调用多个
scan.next()
方法,而没有选中scan.hasNext()
方法
在调用next()
方法之前,请尝试使用scan.hasNext()
它输出的最后一件事是工作是的
似乎循环进入并打印yes
,然后在下一次迭代中抛出异常。
在某个时刻,你会拿出代币进入扫描仪。你的句子完全混淆了,你的代码太大了,无法即时理解。请将其更改为MCVE:请使用缩进,只需从IDE中复制并粘贴格式化文本,大多数IDE将正确格式化和缩进。我知道这是出于安全考虑,但我知道该文件是如何设置的,并且它正确存储了所有内容。在每次查看的最后,我打印出传递的每个值,这样我就可以看到所有内容都存储正确。问题出现在我的第一个switch语句之前,System.out.println(“下一步要做什么>”)从未输出@Hemanthan为什么有两个用于numOfCanAl的for循环?
Exception in thread "main" java.util.NoSuchElementException
at java.util.Scanner.throwFor(Scanner.java:907)
at java.util.Scanner.next(Scanner.java:1416)
at hurry2.main(hurry2.java:91)