Javascript 删除JSON数组的重复键并获取其JSON路径

我的JSON如下所示：

{“回复”：{“结果”：{“线索”：{“行”：[{“LEADID”：“8497300000063017”，“SMOWNERID”：“8497300000061001”}，{“LEADID”：“8497300000063015”，“SMOWNERID”：“8497300000061001”，“HIII”：“你好”}，{“LEADID”：“8497300000063007”，“SMOWNERID”：“8497300000061001”，“BYEE”：“tata”}，{“LEADID”：“8497300000630005”，“SMOWNERID”：“84300000061001”{“849730000000063003”、“SMOWNERID”：“849730000000061001”}，{“LEADID”：“849730000000063001”、“SMOWNERID”：“849730000000061001”}}，}，}，uri:“/crm/private/json/Leads/getMyRecords”}

我需要获取JSON路径，为此我使用了以下代码：

var str={"response":{"result":{"Leads":{"row":[{"LEADID":"849730000000063017","SMOWNERID":"849730000000061001",},
  {"LEADID":"849730000000063015","SMOWNERID":"849730000000061001"},
  {"LEADID":"849730000000063007","SMOWNERID":"849730000000061001","HIII":"hello"},
  {"LEADID":"849730000000063005","SMOWNERID":"849730000000061001","BYEE":"tata"},
  {"LEADID":"849730000000063003","SMOWNERID":"849730000000061001"},
  {"LEADID":"849730000000063001","SMOWNERID":"849730000000061001"}]}},
  "uri":"/crm/private/json/Leads/getMyRecords"}}
var keys = [];
getKeys(keys,str, '');
for(var i=0; i<keys.length; i++) {
  var d=new Array();
  d=keys[i][1].replace(/^\.|\.$/g, '')
  console.log(keys[i][0] + '=' +d)
}
function getKeys(keys, obj, path) {
  for(key in obj) {
    var currpath = path+'.'+key;
    keys.push([key, currpath]);
    if(typeof(obj[key]) === 'object') {
      getKeys(keys, obj[key], currpath);
    }
  }
}

数组元素键是重复的（即）LEADID和SMOWNERID在数组中是重复的。我想删除整个数组的重复项并显示如下输出：

response=response
result=response.result
Leads=response.result.Leads
row=response.result.Leads.row
0=response.result.Leads.row.0
LEADID=response.result.Leads.row.0.LEADID
SMOWNERID=response.result.Leads.row.0.SMOWNERID
HIII=response.result.Leads.row.0.HIII
BYEE=response.result.Leads.row.0.BYEE
uri=response.uri

---

我被困在这里，任何关于这方面的帮助都会非常有用。

将函数

getKeys

修改为：

function getKeys(keys, obj, path) {
  for(key in obj) {
    var currpath = path+'.'+key;
    keys.push([key, currpath]);
    if(typeof(obj[key]) === 'object') {
      if(obj[key] instanceof Array){                   //added check for array
        keys.push(['0', currpath+'.0']);
        getKeys(keys, obj[key][0], currpath+'.0');
      }
      else
      getKeys(keys, obj[key], currpath);
    }
  }
}

更新

---

答案与您想要的不完全一样，但却是我能得到的最接近的答案。此外，您为HIII和BYEE提供的值是错误的。最后，在不同级别上可能有相同的键，但我只匹配键的名称。如果在不同级别上使用相同的键名，则可能不起作用。

另一种方法是将键更改为object from array-将

var-keys=[]

更改为

var-keys={}

，然后更改getKeys方法，如下所示：

function getKeys(keys, obj, path) {
 for(key in obj) {
  var currpath = path+'.'+key;
  if(keys[key])
    continue;
  keys[key] = currpath;
  if(typeof(obj[key]) === 'object') {
    getKeys(keys, obj[key], currpath);
  }
 }
}

---

现在，您还需要更改从getKeys返回后打印值的方式，因为现在keys不是数组而是对象。

：此代码可以工作，但它只打印数组第一个实例的值。如果第二个和第三个实例中有不同的键，我只想防止数组中的重复，该怎么办是gud的起点。如果您对上述问题有任何想法，请提出解决方案

function getKeys(keys, obj, path) {
  for(key in obj) {
    var currpath = path+'.'+key;
    addKeys(key, currpath);
    //keys.push([key, currpath]);
    if(typeof(obj[key]) === 'object') {
      getKeys(keys, obj[key], currpath);
    }
  }
}

function addKeys(key, currpath) {                      //check before adding
  present = keys.map(function(x){return(x[1].split('.').slice(-1)[0])});
  if (present.indexOf(key)==-1){
    keys.push([key, currpath]);
  }
}

function getKeys(keys, obj, path) {
 for(key in obj) {
  var currpath = path+'.'+key;
  if(keys[key])
    continue;
  keys[key] = currpath;
  if(typeof(obj[key]) === 'object') {
    getKeys(keys, obj[key], currpath);
  }
 }
}