Math 计算多个百分比

如果A、B和C不发生，您将如何计算D发生的可能性

例如，防守者有机会闪避、招架或阻挡

    A = 10% chance to evade, 90% chance to not evade
    B = 20% chance to parry, 80% chance to not parry
    C = 40% chance to block, 60% chance to not block
    D = P chance for direct hit
    P = probability that D will occur if A, B, and C do not occur.

如果A不发生，则B将发生等

编辑：所以，要得到一个完全清晰的答案。概率掷骰按以下顺序进行：躲避、招架、阻挡。

若防御者闪避，则防御者不会招架、阻挡或直接被击中

90% chance to not evade * 20% chance to parry = 18% chance to parry

100% - 18% chance to parry = 82% chance to not evade or parry

82% chance to not evade or parry * 40% chance to block = 32.8% chance to block

100% - 32.8% chance to block = 67.2% chance to be hit directly

    A = 10% chance to evade
    B = 18% chance to parry (from 20%)
    C = 32.8% chance to block (from 40%)
    D = 67.2% chance to be hit directly

如果防御者招架，则防御者不会被阻挡或直接命中

90% chance to not evade * 20% chance to parry = 18% chance to parry

100% - 18% chance to parry = 82% chance to not evade or parry

82% chance to not evade or parry * 40% chance to block = 32.8% chance to block

100% - 32.8% chance to block = 67.2% chance to be hit directly

    A = 10% chance to evade
    B = 18% chance to parry (from 20%)
    C = 32.8% chance to block (from 40%)
    D = 67.2% chance to be hit directly

如果防守者阻挡，那么防守者将不会被直接击中

90% chance to not evade * 20% chance to parry = 18% chance to parry

100% - 18% chance to parry = 82% chance to not evade or parry

82% chance to not evade or parry * 40% chance to block = 32.8% chance to block

100% - 32.8% chance to block = 67.2% chance to be hit directly

    A = 10% chance to evade
    B = 18% chance to parry (from 20%)
    C = 32.8% chance to block (from 40%)
    D = 67.2% chance to be hit directly

如果defender未通过上述任何一项，则defender将被直接命中

90% chance to not evade * 20% chance to parry = 18% chance to parry

100% - 18% chance to parry = 82% chance to not evade or parry

82% chance to not evade or parry * 40% chance to block = 32.8% chance to block

100% - 32.8% chance to block = 67.2% chance to be hit directly

    A = 10% chance to evade
    B = 18% chance to parry (from 20%)
    C = 32.8% chance to block (from 40%)
    D = 67.2% chance to be hit directly

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这取决于如何考虑躲避招架和拦网机会

如果掷骰结果不同，例如你在

[0100）

中掷了一个数字，你就有了

0-9 evade
10-29 parry
30-69 block
70-99 nothing

那么它就是

1-（A+B+C）=0.30=30%

如果它们是独立的卷，那么你必须考虑不通过每个卷的机会：

10% evade : 90% of not evading
20% parry : 80% of not parrying
40% block: 60% of not blocking

虽然它们是3个单独的轧辊，所以你必须将它们相乘，因为你要考虑不通过三个轧辊的概率：

(1-A)*(1-B)*(1-C) = 0.432 = 43.2%

例如（“如果A不发生，那么B将发生等”）：

10%（0.1）躲闪=>90%的攻击不躲闪，可以招架或阻挡

20%（0.2）对不闪避攻击进行招架=>（80%的不闪避攻击可以进行招架）=>0所有攻击中只有18%（0.9不闪避*0.2）可以进行招架=>82%的不闪避和不闪避攻击可以进行阻挡

40%（0.4）阻止不闪避和不招架攻击=>（60%的不闪避和不招架攻击可以招架）=>所有攻击中只有32.8%（0.82%的不闪避和不招架*0.4）可以阻止=>67.2%的不闪避、不招架和不阻挡攻击。

防御=32.8%

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对于某些序列（如us，C->B->A）防守轮换可能是另一个结果。

这个问题与数学有关，而不是与编程操作有关。哦，我想我现在知道了。所以如果我理解正确，我们首先进行躲避掷骰。然后我们有90%的机会招架，得到18%。最后，你需要从90%中减去之前的答案，得到82%。真正的概率是获得成功招架掷骰的几率为18%，但要继续进行格挡掷骰，我们需要使用82%*.4获得32.8%的格挡几率。因此，现在有67.2%的几率你会被直接命中。对不起，关于防御方面我有点不清楚，我的意思是直接命中。是的，我们有67.2%的几率直接命中你的轮换：逃避->招架->拦网好吧，非常感谢！这个问题已经困扰了我好几年了，哈哈。在我之前的评论中，我想用100%而不是第二个90%