Mysql中创建逻辑视图的查询应该是什么?

Mysql中创建逻辑视图的查询应该是什么?,mysql,Mysql,我必须在mysql中编写一个查询。下面是我的ad_显示表 ad_displaysId | adv_id | campaign_id | adtypeId | clicked(boolean) 我有另一个表名作为广告,它有广告id ad_id | advertisename CampPaignId在此表名中为camp_表 campaign_id | camp_name adtypeId在此表名中作为adtype adtypeId | adtype_name 现在我想创建一个视图,从我的a

我必须在mysql中编写一个查询。下面是我的ad_显示表

ad_displaysId |  adv_id | campaign_id | adtypeId | clicked(boolean)
我有另一个表名作为广告,它有广告id

ad_id | advertisename
CampPaignId在此表名中为camp_表

campaign_id | camp_name
adtypeId在此表名中作为adtype

adtypeId | adtype_name
现在我想创建一个视图,从我的ad_显示表中得到这样的结果

advertise_name | camp_name | adtype_name | count_of_clicked | count_of_row
这里

我能提供的额外信息是……在广告显示中,有多个条目具有相同的广告id、相同的营地id、相同的广告类型id和点击的合谋是真还是假

我是mysql的新手。有人能建议我用mysql做这个吗?

试试这个:

create view my_ad_view as
select
    advertise_name,
    camp_name,
    adtype_name,
    sum(clicked) as count_of_clicked,
    count(*) as count_of_row
from ad_display ad
left join advertise a on a.ad_id = ad.ad_displaysId
left join camp_table ct on ct.campaign_id = ad.campaign_id
left join adtype at on at.adtypeId = ad.adtypeId 
group by advertise_name, camp_name, adtype_name
请注意
sum(单击)
的漂亮“技巧”,这是因为在mysql中
true
1
false
0
,所以布尔值求和会计算其为真的次数

create view my_ad_view as
select
    advertise_name,
    camp_name,
    adtype_name,
    sum(clicked) as count_of_clicked,
    count(*) as count_of_row
from ad_display ad
left join advertise a on a.ad_id = ad.ad_displaysId
left join camp_table ct on ct.campaign_id = ad.campaign_id
left join adtype at on at.adtypeId = ad.adtypeId 
group by advertise_name, camp_name, adtype_name