Objective c 联系人获取问题

我们正在使用CNContactStore从iphone获取联系人，但我们正在从我的iphone获取所有联系人，这也提供了所有同步联系人，如facebook和其他gmail联系人，但我只需要获取存储在iphone中的联系人。如何做到这一点，请帮我摆脱困境。

导入这些

#import <AddressBook/AddressBook.h>
#import <AddressBookUI/AddressBookUI.h>


- (void) fetchContactsFromDevice {

//1
CFErrorRef error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);

if (addressBook != nil) {

    ABAddressBookRequestAccessWithCompletion( addressBook, ^(bool granted, CFErrorRef error) {

        if (error) {
            NSLog(@"ABAddressBookRequestAccessWithCompletion error: %@", CFBridgingRelease(error));
        }

        if (granted) {
            // if they gave you permission, then just carry on

            [self listPeopleInAddressBook:addressBook];
        } else {
            // however, if they didn't give you permission, handle it gracefully, for example...

            dispatch_async(dispatch_get_main_queue(), ^{
                // BTW, this is not on the main thread, so dispatch UI updates back to the main queue

                [[[UIAlertView alloc] initWithTitle:nil message:@"" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil] show];
            });
        }

        CFRelease(addressBook);

    });

} else { 

    NSLog(@"Error reading Address Book : %@", error);
}

#导入
#进口
-（void）从设备获取联系人{
//1
CFErrorRef error=NULL；
ABAddressBookRef addressBook=ABAddressBookCreateWithOptions（NULL，错误（&R）；
如果（地址簿！=nil）{
ABAddressBookRequestAccessWithCompletion（addressBook，^（已授予bool，CFErrorRef错误）{
如果（错误）{
NSLog（@“ABAddressBookRequestAccessWithCompletion错误：%@”，CfBrigingRelease（错误））；
}
如果（授予）{
//如果他们允许你，那就继续吧
[self-listPeopleInAddressBook:addressBook]；
}否则{
//但是，如果他们没有给你许可，你可以优雅地处理，例如。。。
dispatch\u async（dispatch\u get\u main\u queue（）^{
//顺便说一句，这不在主线程上，因此调度UI更新回主队列
[[UIAlertView alloc]initWithTitle:nil消息：@“委托：nil取消按钮：@“确定”其他按钮：nil]show]；
});
}
CFRelease（通讯录）；
});
}否则{
NSLog（@“读取通讯簿时出错：%@”，错误）；
}

}

此方法将帮助您仅获取通讯簿号码

然后用它来绘图

- (void)listPeopleInAddressBook:(ABAddressBookRef)addressBook {

NSArray *allPeople = CFBridgingRelease(ABAddressBookCopyArrayOfAllPeople(addressBook));
NSInteger numberOfPeople = [allPeople count];

for (NSInteger i = 0; i < numberOfPeople; i++) {
    ABRecordRef person = (__bridge ABRecordRef)allPeople[i];

    NSMutableDictionary * user = [[NSMutableDictionary alloc] init];

    NSString *firstName = CFBridgingRelease(ABRecordCopyValue(person, kABPersonFirstNameProperty));
    NSString *lastName  = CFBridgingRelease(ABRecordCopyValue(person, kABPersonLastNameProperty));

    [user setObject:firstName forKey:@"firstname"];
    [user setObject:lastName forKey:@"lastname"];


    ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);

    CFIndex numberOfPhoneNumbers = ABMultiValueGetCount(phoneNumbers);
    for (CFIndex i = 0; i < numberOfPhoneNumbers; i++) {
        NSString *phoneNumber = CFBridgingRelease(ABMultiValueCopyValueAtIndex(phoneNumbers, i));

        [user setObject:phoneNumber forKey:@"phoneNumbers"];
    }

    CFRelease(phoneNumbers);

    [self.contactDataArray addObject:user];
}

[yourtable reloadData];

-（void）listPeopleInAddressBook:（ABAddressBookRef）addressBook{
NSArray*allPeople=CfBrigingRelease（abAddressBookCopyArrayFallPeople（addressBook））；
NSInteger numberOfPeople=[allPeople count]；
对于（NSInteger i=0；i

}

---

希望这将有助于

任何人都了解上述问题如果您查看

[store Containers Matching Predicate:nil error:&error]

，是否会获得多次点击（即一次点击FB，一次点击gmail等）？如果是这样，您可以使用

谓词ForContactsInContainerWithiIdentifier:

仅获取感兴趣的容器的联系人。他询问的是联系人框架，而不是地址簿框架（除非您需要支持较旧的操作系统版本，否则不应使用该框架）。顺便说一句，这段代码看起来很像另一个答案中的代码：我真的很抱歉，但这段代码来自我的项目实现，但我知道这对他有帮助。