如何在PHP中合并问题和选项数组？

我对使用Laravel和处理数组中的数据仍然是新手

基本上我有两个需要合并的表

首先是问题，其次是选择

这是我的问题列表

[0] => Array (
    [id] => 1
    [question] => What major problem are Texans having?
    )
[1] => Array (
    [id] => 2
    [question] => What did civic leaders suggest?
    )
[2] => Array (
    [id] => 3
    [question] => What is the author’s general intention in writing this article?
    )

    $questions = Question::select(
      'question.id',
      'question.component AS question',
    )
    ->from('questions AS question')
    ->leftJoin('scenarios AS scenario', 'scenario.id', '=', 'question.scenario_id')
    ->where('question.scenario_id',1)
    ->get()
    ->toArray();

    $choices = Question_choice::select(
      'choice.question_id',
      'choice AS choice'
    )
    ->from('question_choices AS choice')
    ->leftJoin('questions AS question', 'question.id', '=', 'choice.question_id')
    ->where('question.id', ```looping the id data that i have in the question table```)
    ->get()
    ->toArray();

这是我的选择数组

[0] => Array (
    [question_id] => 1
    [choice] => gas shortage
    )
[1] => Array (
    [question_id] => 1
    [choice] => panic buying
    )
[2] => Array (
    [question_id] => 1
    [choice] => Hurricane Harvey
    )
[3] => Array (
    [question_id] => 1
    [choice] => help from oil companies
    )
[4] => Array (
    [question_id] => 2
    [choice] => gas shortage
    )
[5] => Array (
    [question_id] => 2
    [choice] => panic buying
    )
[6] => Array (
    [question_id] => 2
    [choice] => Hurricane Harvey
    )
[7] => Array (
    [question_id] => 2
    [choice] => help from oil companies
    )
[8] => Array (
    [question_id] => 3
    [choice] => gas shortage
    )
[9] => Array (
    [question_id] => 3
    [choice] => panic buying
    )
[10] => Array (
    [question_id] => 3
    [choice] => Hurricane Harvey
    )
[11] => Array (
    [question_id] => 3
    [choice] => help from oil companies
    )

我在考虑如何根据选择的问题组合这两个数组？因此，当我在视图中显示它时，它将非常容易。我不知道如何使用多维数组，我在这里寻求如何使用多维数组的帮助

下面是我目前获取数据的代码

这是用来回答问题的

[0] => Array (
    [id] => 1
    [question] => What major problem are Texans having?
    )
[1] => Array (
    [id] => 2
    [question] => What did civic leaders suggest?
    )
[2] => Array (
    [id] => 3
    [question] => What is the author’s general intention in writing this article?
    )

    $questions = Question::select(
      'question.id',
      'question.component AS question',
    )
    ->from('questions AS question')
    ->leftJoin('scenarios AS scenario', 'scenario.id', '=', 'question.scenario_id')
    ->where('question.scenario_id',1)
    ->get()
    ->toArray();

    $choices = Question_choice::select(
      'choice.question_id',
      'choice AS choice'
    )
    ->from('question_choices AS choice')
    ->leftJoin('questions AS question', 'question.id', '=', 'choice.question_id')
    ->where('question.id', ```looping the id data that i have in the question table```)
    ->get()
    ->toArray();

这是为了得到问题的选择

[0] => Array (
    [id] => 1
    [question] => What major problem are Texans having?
    )
[1] => Array (
    [id] => 2
    [question] => What did civic leaders suggest?
    )
[2] => Array (
    [id] => 3
    [question] => What is the author’s general intention in writing this article?
    )

    $questions = Question::select(
      'question.id',
      'question.component AS question',
    )
    ->from('questions AS question')
    ->leftJoin('scenarios AS scenario', 'scenario.id', '=', 'question.scenario_id')
    ->where('question.scenario_id',1)
    ->get()
    ->toArray();

    $choices = Question_choice::select(
      'choice.question_id',
      'choice AS choice'
    )
    ->from('question_choices AS choice')
    ->leftJoin('questions AS question', 'question.id', '=', 'choice.question_id')
    ->where('question.id', ```looping the id data that i have in the question table```)
    ->get()
    ->toArray();

我的想法是这样的

[0] => Array (
    [id] => 1
    [question] => What major problem are Texans having?
       =>[choices] =>[0] gas shortage
                     [1] panic buying
                     [2] Hurricane Harvey
                     [3] help from oil companies
    )

---

我不知道我是否讲得通，任何帮助都将不胜感激。我真的被我现在正在做的事情困住了。

欢迎来到Stack Overflow

在拉威尔，你可以使用

当使用Eloquent时，您不需要编写自己的查询，Eloquent将管理关系

创建一个模型并使用

hasMany

<?php

namespace App\Model;

use Illuminate\Database\Eloquent\Model;

class Question extends Model
{
    

    public function choices()
    {
        return $this->hasMany('App\Model\Choice', 'question_id');
    }

}

---

欢迎来到堆栈溢出

在拉威尔，你可以使用

当使用Eloquent时，您不需要编写自己的查询，Eloquent将管理关系

创建一个模型并使用

hasMany

<?php

namespace App\Model;

use Illuminate\Database\Eloquent\Model;

class Question extends Model
{
    

    public function choices()
    {
        return $this->hasMany('App\Model\Choice', 'question_id');
    }

}

---

我建议使用集合来处理它。因此，如果我们假设您已经有一系列的问题和答案，下面的一段代码将满足您的需要。关键是它不需要对数据库进行任何查询，所有进程都将在应用程序层处理

$questions = [...]; // array of questions
$answers = [...]; // array of answers 

$questionsCollection = new Collection($questions);
$answersCollection = new Collection($answers);

$groupedAnswers = $answersCollection->groupBy('question_id');
$questionAndAnswers = $groupedAnswers->map( function ($choices, $questionId) use ($questionsCollection) {
    $question = $questionsCollection->where('id', $questionId)->first();
    $question['choices'] = $choices;
    return $question;
});

简要说明我在代码中做什么：

• 我正在使用所需的数组创建集合的实例。因此，我可以在使用收集方法时使用数组的数据
• 所有选项根据问题id分组在一起
• 通过使用“map”方法及其回调，我们可以迭代答案，并使用“where”方法和每次迭代中可用的问题id查找相关问题

---

我建议使用集合来处理它。因此，如果我们假设您已经有一系列的问题和答案，下面的一段代码将满足您的需要。关键是它不需要对数据库进行任何查询，所有进程都将在应用程序层处理

$questions = [...]; // array of questions
$answers = [...]; // array of answers 

$questionsCollection = new Collection($questions);
$answersCollection = new Collection($answers);

$groupedAnswers = $answersCollection->groupBy('question_id');
$questionAndAnswers = $groupedAnswers->map( function ($choices, $questionId) use ($questionsCollection) {
    $question = $questionsCollection->where('id', $questionId)->first();
    $question['choices'] = $choices;
    return $question;
});

简要说明我在代码中做什么：

• 我正在使用所需的数组创建集合的实例。因此，我可以在使用收集方法时使用数组的数据
• 所有选项根据问题id分组在一起
• 通过使用“map”方法及其回调，我们可以迭代答案，并使用“where”方法和每次迭代中可用的问题id查找相关问题

---

您好，先生，我试过了，但结果是，它获取了选项表中的所有数据，但我只想根据我在问题表数据中的id获取选项中的数据。关系用于获取结果，就像您稍后所说的那样。如果您正确使用它，在foreach中您将有疑问和它的选择，下一次迭代将有疑问和它的选择，等等……在控制器中，您可以像

question:：with（'choices'）->get（）@Rinto George请帮我回答这个问题。您好，先生，我试过了，但输出是，它获取选项表中的所有数据，但我只想根据我在问题表数据中的id获取选项中的数据。关系用于获取结果，就像您稍后所说的那样。如果您正确使用它，在foreach中您将有疑问和它的选择，下一次迭代将有疑问和它的选择，等等……在控制器中，您可以像
question:：with（'choices'）->get（）@Rinto George请帮我回答这个问题。不要使用
leftJoin
，尝试
eagar加载
，这是laravel雄辩的方法。我建议@Rinto George answer不要使用
leftJoin
，尝试
eagar加载
，这是laravel雄辩的方法。我推荐@Rinto-George-answer