Python 3.2.1:Can';t索引形状,以后需要访问特定的矩形

Python 3.2.1:Can';t索引形状,以后需要访问特定的矩形,python,graphics,indexing,Python,Graphics,Indexing,我正在使用嵌套的for循环绘制一个包含10行矩形和10列矩形的网格(总共100个): 我知道矩形不支持索引(如我得到的TypeError中所示),但我需要能够在以后的代码中访问一个特定的矩形 是否有一种方法可以对每个矩形进行索引,以便我以后可以沿着网格块[3][7]的线条做一些事情(当然,现在的方式不允许这样做)?顺便说一句,我目前不知道像\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

我正在使用嵌套的
for
循环绘制一个包含10行矩形和10列矩形的网格(总共100个):

我知道
矩形
不支持索引(如我得到的TypeError中所示),但我需要能够在以后的代码中访问一个特定的矩形


是否有一种方法可以对每个矩形进行索引,以便我以后可以沿着网格块[3][7]的线条做一些事情(当然,现在的方式不允许这样做)?顺便说一句,我目前不知道像
\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

gridTiles = []

for r in range(totalSpaces):
    row = []

    for c in range(totalSpaces):
        tiles = Rectangle(Point(borderSet + r * spaceSize, borderSet + c * spaceSize), Point(borderSet + (r + 1) * spaceSize, borderSet + (c + 1) * spaceSize))
        tiles.setWidth(2)
        tiles.draw(board)

        row.append(tiles)
    gridTiles.append(row)
现在,您应该能够按照自己的意愿编制索引:

gridTiles[0][0]

代码中的任何内容都不应提供索引器。请显示给您一个问题的代码和确切错误。非常感谢。您的索引方法非常有效。这让我一天中的大部分时间都在打转。
gridTiles[0][0]