Python datetime对象的算法

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我使用today函数获取当前日期，如何在此对象上执行简单的算术，以便将当前日期减少或增加1或2（即昨天或前天）

您可以执行以下操作

In [6]: import datetime

# Today
In [7]: datetime.datetime.now()
Out[7]: datetime.datetime(2013, 1, 15, 15, 31, 10, 760000)

# Tomorrow's date
In [8]: print datetime.datetime.now() + datetime.timedelta(days=1)
2013-01-16 15:31:15.336000

# Day after tomorrow's day
In [9]: print datetime.datetime.now() + datetime.timedelta(days=2)
2013-01-17 15:31:52.601000

# Yesterday's date
In [10]: print datetime.datetime.now() - datetime.timedelta(days=1)
2013-01-14 15:32:00.081000

也适用于datetime.datetime.today（）

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您可以执行以下操作

In [6]: import datetime

# Today
In [7]: datetime.datetime.now()
Out[7]: datetime.datetime(2013, 1, 15, 15, 31, 10, 760000)

# Tomorrow's date
In [8]: print datetime.datetime.now() + datetime.timedelta(days=1)
2013-01-16 15:31:15.336000

# Day after tomorrow's day
In [9]: print datetime.datetime.now() + datetime.timedelta(days=2)
2013-01-17 15:31:52.601000

# Yesterday's date
In [10]: print datetime.datetime.now() - datetime.timedelta(days=1)
2013-01-14 15:32:00.081000

也适用于datetime.datetime.today（）

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您可能对python librarydatetime的timedelta模块感兴趣。您可以使用它。您可能对python librarydatetime的timedelta模块感兴趣。你可以用它。