Python 从数据帧的列中筛选出关键字（不区分大小写）-不区分大小写

要基于现有列中的单词创建新列吗 新栏应为大厅、UPS、电气或“空白区”

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如上所述，搜索应不区分大小写，如果找到“Electric”或“Electric”，则结果应为“Electric”

我为您提供了一个解决方案。它检查字符串之间是否匹配，如果找到，则将其添加到将成为新列的列表中

import pandas as pd 


d = { "Name" : ["Sensor - Bank lobby ", "Sensor - Bank Lobby ", "Temperature - UPS Room", "Sensor - Electric Room ", "Sensor - electrical Room", "Sensor"]}


df = pd.DataFrame(data=d)

list_sub_units = []

list_matches = ["Lobby", "UPS", "Electric"]

for entry in df["Name"]:
    matched = False

    for match in list_matches:
        if entry.lower().find(match.lower()) > 0:
            list_sub_units.append(match)
            matched = True
        
    if not matched:
        list_sub_units.append("")

df["SubUnitName"] = list_sub_units


print(df)

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在“Name”列中建立要查找的单词列表，然后应用函数“find_match”创建新的“Name”列

将“无”替换为最后一行的空白

df["SubUnitName"].fillna('', inplace=True)

search_list = ["Lobby", "UPS", "Electric"]


def find_match(name_str: str) -> str:
    for item in search_list:
        item_lc = item.lower()
        if item_lc in name_str.lower():
            return item


df.loc[:, "SubUnitName"] = df["Name"].apply(find_match)

df["SubUnitName"].fillna('', inplace=True)