Python字符串比较

我想用wp_扫描来扫描我的wordpress网站，寻找新的插件。 我想有一个python脚本，每天给我看

• 易受攻击插件的列表
• 新插件的列表

编写一个只提供输出中易受攻击插件的解析器并不复杂。但是如何编写解析器（或以何种方式编写），以便只获得新插件的列表

示例-（示例的源代码-我稍微修改了一下）。 第一天：

___________________________________________________
__          _______   _____
\ \        / /  __ \ / ____|
\ \  /\  / /| |__) | (___   ___  __ _ _ __
\ \/  \/ / |  ___/ \___ \ / __|/ _` | '_ \
\  /\  /  | |     ____) | (__| (_| | | | |
\/  \/   |_|    |_____/ \___|\__,_|_| |_| v2.1rNA
WordPress Security Scanner by the WPScan Team
Sponsored by the RandomStorm Open Source Initiative
_____________________________________________________
| URL: http://www.blackmoreops.com/
| Started on Sun Oct 13 13:39:25 2013
[31m[!][0m The WordPress 'http://www.blackmoreops.com/readme.html' file exists
[31m[!][0m Full Path Disclosure (FPD) in 'http://www.blackmoreops.com/wp-includes/rss-functions.php'
[32m[+][0m XML-RPC Interface available under http://www.blackmoreops.com/xmlrpc.php
[32m[+][0m WordPress version 3.6.1 identified from meta generator
[32m[+][0m The WordPress theme in use is twentyten v1.6
| Name: twentyten v1.6
| Location: http://www.blackmoreops.com/wp-content/themes/twentyten/
[32m[+][0m Enumerating plugins from passive detection ...
2 plugins found :
| Name: add-to-any v1.2.5
| Location: http://www.blackmoreops.com/wp-content/plugins/add-to-any/
| Directory listing enabled: Yes
| Readme: http://www.blackmoreops.com/wp-content/plugins/add-to-any/README.txt
| Name: captcha v3.8.4
| Location: http://www.blackmoreops.com/wp-content/plugins/captcha/
| Directory listing enabled: Yes
| Readme: http://www.blackmoreops.com/wp-content/plugins/captcha/readme.txt
[32m[+] Finished at Sun Oct 13 13:39:51 2013[0m
[32m[+] Elapsed time: 00:00:26[0m]

第二天：

___________________________________________________
__          _______   _____
\ \        / /  __ \ / ____|
\ \  /\  / /| |__) | (___   ___  __ _ _ __
\ \/  \/ / |  ___/ \___ \ / __|/ _` | '_ \
\  /\  /  | |     ____) | (__| (_| | | | |
\/  \/   |_|    |_____/ \___|\__,_|_| |_| v2.1rNA
WordPress Security Scanner by the WPScan Team
Sponsored by the RandomStorm Open Source Initiative
_____________________________________________________
| URL: http://www.blackmoreops.com/
| Started on Sun Oct 13 13:39:25 2013
[31m[!][0m The WordPress 'http://www.blackmoreops.com/readme.html' file exists
[31m[!][0m Full Path Disclosure (FPD) in 'http://www.blackmoreops.com/wp-includes/rss-functions.php'
[32m[+][0m XML-RPC Interface available under http://www.blackmoreops.com/xmlrpc.php
[32m[+][0m WordPress version 3.6.1 identified from meta generator
[32m[+][0m The WordPress theme in use is twentyten v1.6
| Name: twentyten v1.6
| Location: http://www.blackmoreops.com/wp-content/themes/twentyten/
[32m[+][0m Enumerating plugins from passive detection ...
3 plugins found :
| Name: add-to-any v1.2.5
| Location: http://www.blackmoreops.com/wp-content/plugins/add-to-any/
| Directory listing enabled: Yes
| Readme: http://www.blackmoreops.com/wp-content/plugins/add-to-any/README.txt
| Name: captcha v3.8.4
| Location: http://www.blackmoreops.com/wp-content/plugins/captcha/
| Directory listing enabled: Yes
| Readme: http://www.blackmoreops.com/wp-content/plugins/captcha/readme.txt
| Name: google-analyticator v6.4.5
| Location: http://www.blackmoreops.com/wp-content/plugins/google-analyticator/
| Directory listing enabled: Yes
| Readme: http://www.blackmoreops.com/wp-content/plugins/google-analyticator/readme.txt
[32m[+] Finished at Sun Oct 14 13:39:51 2013[0m
[32m[+] Elapsed time: 00:00:26[0m]

我是否应该总是在[+]后面分隔字符串并比较它们 （我不知道输出列表是如何排序的——我想是alpahbetic——所以我不能只得到最后的插件，然后说这是我的新插件）？效率高吗？让问题变得简单：

第一个字符串：

Hallo
Pet
Me

第二个字符串：

Hallo
World
Pet
Me

---

我如何有效地找出新词？

解决您的简化示例：

str1 = "Hallo Pet Me"
str2 = "Hallo World Pet Me"

set1 = set(str1.split())
set2 = set(str2.split())
print set2 - set1

---

您有两组字符串，希望获得第二组但不在第一组中的字符串。

首先在列表中拆分字符串，然后打印第二个字符串中的每个单词，因为它不是第一个字符串

    str1 = "Hallo Pet Me"
    str2 = "Hallo World Pet Me"
    split1 = str1.split()
    split2 = str2.split()
    print [word for word in split2 if word not in split1]

如果要忽略小写/大写的差异：

    str1 = "Hallo Pet Me"
    str2 = "Hallo World Pet Me"
    split1 = str1.lower().split()
    split2 = str2.lower().split()
    print [word for word in split2 if word not in split1]

---

如果两个文本的字符串相同，是否可以比较它们？是否可以使用列表进行比较？因为我将输出保存为列表。@Loreta只需将结果集转换为列表：

list（set2-set1）

。