SQL查询-理解我的查询中的错误

我有一个查询-我需要帮助返回更多的列

我需要返回的是

• OrderHeader.receiver
• OrderHeader.receiver_name 1
• 订单详细信息。数量
• 发货日期
• 托运。意味着估计的成本

以下是我目前掌握的代码：

WITH cte AS
(
    SELECT 
        Consignments.consignment_number, UserReferences.value, 
        Consignments.despatch_date
    FROM 
        Consignments
    INNER JOIN 
        OrderDetail ON Consignments.consignment_id = OrderDetail.consignment_id
    INNER JOIN 
        OrderHeader ON OrderDetail.order_id = OrderHeader.order_id
    INNER JOIN 
        UserReferences ON OrderDetail.record_id = UserReferences.record_id
    WHERE 
        Consignments.despatch_date = '2020-04-24'
)
SELECT
    '11' AS RecordType, t.consignment_number,
    '' AS ' ', '' AS ' ', '' AS ' ', '' AS ' ', 
    STUFF((SELECT ', ' + CONVERT(varchar(255), t1.value)
           FROM cte t1 
           WHERE t1.consignment_number = t.consignment_number
           FOR XML PATH('')), 1, 1, '') AS senders_reference
FROM
    (SELECT DISTINCT consignment_number FROM cte t) t;

我曾尝试将所需列添加到SELECT中，但在添加时出现错误，例如：

Msg 4104，16级，状态1，第12行
无法绑定多部分标识符“OrderHeader.receiver_index”

---

如果您对此有任何帮助，我们将不胜感激。

缺少的字段应与

cte一起出现。

：

WITH cte AS
(     SELECT Consignments.consignment_number, 
             UserReferences.value, Consignments.despatch_date,
             OrderHeader.receiver, OrderHeader.receiver_name1
             OrderDetail.quantity, Consignments.despatch_date
             Consignments.connote_estimated_cost
       FROM Consignments INNER JOIN 
            OrderDetail 
            ON Consignments.consignment_id = OrderDetail.consignment_id INNER JOIN 
            OrderHeader 
            ON OrderDetail.order_id = OrderHeader.order_id INNER JOIN 
            UserReferences 
            ON OrderDetail.record_id = UserReferences.record_id
       WHERE Consignments.despatch_date = '2020-04-24'
)
SELECT DISTINCT '11' AS RecordType, t.*,
       '' AS ' ', '' AS ' ', '' AS ' ', '' AS ' ', 
       STUFF((SELECT DISTINCT ', ' + CONVERT(varchar(255), t1.value)
              FROM cte t1 
              WHERE t1.consignment_number = t.consignment_number
              FOR XML PATH('')
             ), 1, 1, '') AS senders_reference
FROM CTE t;

---

该查询生成该错误的唯一方法是其中一个“表”实际上是一个视图，而该视图有一个错误。但是，我怀疑您已经简化了查询并找出了错误的来源。请确保此处显示的查询实际生成您引用的错误消息。这是完整的错误消息消息4104，级别16，状态1，第12行。无法绑定多部分标识符“OrderHeader.receiver_index”。您的查询中是否有

视图

？第12行未提及该标识符。请编辑您的问题，以实际显示实际生成该消息的实际代码！不幸的是，现在UserReferences.value在第一个SELECT语句中-我遇到了我的原始问题，有多行具有相同的寄售编号。。。有没有办法删除第二列中对UserReferences.value的第一个引用，并在末尾保留senders\u引用列？