String 将系统日期与文本文件中的日期进行比较

我得到文本文件中的日期并将其分配给变量。当我从文件中记下日期时，我得到了这个

Not After : Jul 28 14:09:57 2017 GMT

所以我只能用这个命令裁剪出日期

echo $dateFile | cut -d ':' -f 2,4

结果将是

Jul 28 14:57 2017 GMT

如何将此日期转换为秒数，以便与系统日期进行比较？如果超过2天

我有这个代码，但它不工作。我运行时收到一条错误消息。我认为这是因为$dateFile是一个文本文件，它不知道如何转换它。任何帮助都将不胜感激

#!/bin/bash

$dateFile=grep "After :" myfile.txt | cut -d ':' -f 2,4

AGE_OF_MONTH="172800" # 172800 seconds  = 2 Days
NOW=$( date +%s )
NEW_DATE=$(( NOW - AGE_OF_MONTH ))

if [ $( stat -c %Y "$dateFile" ) -lt ${NEW_DATE} ]; then
   echo Date Less then 2 days
else
   echo Date Greater then 2 days
fi

---

您的脚本中有几个错误。请尝试以下方法：

#!/bin/bash

# capture the seconds since epoch minus 2 days
NOW=`expr $(date '+%s') - 172800`  

# read every line in the file myfile.txt
while read -r line;
do
  # remove the unwanted words and leave only the date info
  s=`echo $line | cut -d ':' -f 2,4`
  # parse the string s into a date and capture the number of seconds since epoch
  date=$(date -d "$s" '+%s')

  # compare and print output
  if [ $date -lt $NOW ]; then
    echo "Date Less then 2 days, s=$s, date=$date, now=$NOW"
  else
    echo "Date Greater then 2 days, s=$s, date=$date, now=$NOW"
  fi
done < myfile.txt

grep和while的示例：

#!/bin/sh

dateFile=`grep "After :" my.txt | cut -d ':' -f 2,4`

# capture the seconds since epoch minus 2 days
NOW=`expr $(date '+%s') - 172800`

echo "$dateFile" | while read -r line;
do
  # parse the string s into a date and capture the number of seconds since epoch
  date=$(date -d "$line" '+%s')

  # compare and print output
  if [ $date -lt $NOW ]; then
    echo "Date Less then 2 days, s=$line, date=$date, now=$NOW"
  else
    echo "Date Greater then 2 days, s=$line, date=$date, now=$NOW"
  fi
done

#!/bin/sh

# capture the seconds since epoch minus 2 days
NOW=`expr $(date '+%s') - 172800`

grep "After :" myFile.txt | cut -d ':' -f 2,4 | while read -r line;
do
  # parse the string s into a date and capture the number of seconds since epoch
  date=$(date -d "$line" '+%s')

  # compare and print output
  if [ $date -lt $NOW ]; then
    echo "Date Less then 2 days, s=$line, date=$date, now=$NOW"
  else
    echo "Date Greater then 2 days, s=$line, date=$date, now=$NOW"
  fi
done

---

希望这能澄清您的问题。

您的脚本中有几个错误。请尝试以下方法：

#!/bin/bash

# capture the seconds since epoch minus 2 days
NOW=`expr $(date '+%s') - 172800`  

# read every line in the file myfile.txt
while read -r line;
do
  # remove the unwanted words and leave only the date info
  s=`echo $line | cut -d ':' -f 2,4`
  # parse the string s into a date and capture the number of seconds since epoch
  date=$(date -d "$s" '+%s')

  # compare and print output
  if [ $date -lt $NOW ]; then
    echo "Date Less then 2 days, s=$s, date=$date, now=$NOW"
  else
    echo "Date Greater then 2 days, s=$s, date=$date, now=$NOW"
  fi
done < myfile.txt

grep和while的示例：

#!/bin/sh

dateFile=`grep "After :" my.txt | cut -d ':' -f 2,4`

# capture the seconds since epoch minus 2 days
NOW=`expr $(date '+%s') - 172800`

echo "$dateFile" | while read -r line;
do
  # parse the string s into a date and capture the number of seconds since epoch
  date=$(date -d "$line" '+%s')

  # compare and print output
  if [ $date -lt $NOW ]; then
    echo "Date Less then 2 days, s=$line, date=$date, now=$NOW"
  else
    echo "Date Greater then 2 days, s=$line, date=$date, now=$NOW"
  fi
done

#!/bin/sh

# capture the seconds since epoch minus 2 days
NOW=`expr $(date '+%s') - 172800`

grep "After :" myFile.txt | cut -d ':' -f 2,4 | while read -r line;
do
  # parse the string s into a date and capture the number of seconds since epoch
  date=$(date -d "$line" '+%s')

  # compare and print output
  if [ $date -lt $NOW ]; then
    echo "Date Less then 2 days, s=$line, date=$date, now=$NOW"
  else
    echo "Date Greater then 2 days, s=$line, date=$date, now=$NOW"
  fi
done

---

希望这能澄清您的问题。

您的代码工作得非常好。非常感谢。只是想知道为什么你需要一个循环来读取文件中的每一行，因为grep命令会自动获取你需要的信息？？？为了回答你的问题，我编辑了我的答案。如果您对它感到满意，请选择它作为正确答案。您的代码工作正常。非常感谢。只是想知道为什么你需要一个循环来读取文件中的每一行，因为grep命令会自动获取你需要的信息？？？为了回答你的问题，我编辑了我的答案。如果您对它感到满意，请选择它作为正确答案。