Coq:不充分的对正错误
我是Coq新手,假设H3的理由不足。我试着重写了好几次,但错误依然存在。有人能解释一下原因吗?谢谢Coq:不充分的对正错误,coq,Coq,我是Coq新手,假设H3的理由不足。我试着重写了好几次,但错误依然存在。有人能解释一下原因吗?谢谢 Section GroupTheory. Variable G: Set. Variable operation: G -> G -> G. Variable e : G. Variable inv : G -> G. Infix "*" := operation. Hypothesis associativity : forall x y z : G, (x * y) * z
Section GroupTheory.
Variable G: Set.
Variable operation: G -> G -> G.
Variable e : G.
Variable inv : G -> G.
Infix "*" := operation.
Hypothesis associativity : forall x y z : G, (x * y) * z = x * (y * z).
Hypothesis identity : forall x : G, exists e : G, (x * e = x) /\ (e * x = x).
Hypothesis inverse : forall x : G, (x * inv x = e) /\ (inv x * x = e).
Theorem latin_square_property :
forall a b : G, exists x : G, a * x = b.
proof.
let a : G, b : G.
take (inv a * b).
have H1:(a * (inv a * b) = (a * inv a) * b) by associativity.
have H2:(a * inv a = e) by inverse.
have H3:(e * b = b) by identity.
have (a * (inv a * b) = (a * inv a) * b) by H1.
~= (e * b) by H2.
~= (b) by H3.
hence thesis.
end proof.
Qed.
End GroupTheory.
原因是您的
身份
公理独立于本节中定义的单位e
,因为您已将e
与身份
公理定义中的存在量词绑定
我们可以修改identity
,去掉定义中存在的e
:
Hypothesis identity : forall x : G, (x * e = x) /\ (e * x = x).
然后你就可以完成你的证明了。就是这样。谢谢