Ios 如何在启用ARC的情况下检索使用UIImagePickerControllerDelegate拍摄的图像?
我有一个应用程序,需要拍摄一张照片,然后显示给用户。我打开相机,让用户使用以下代码拍照:Ios 如何在启用ARC的情况下检索使用UIImagePickerControllerDelegate拍摄的图像?,ios,objective-c,Ios,Objective C,我有一个应用程序,需要拍摄一张照片,然后显示给用户。我打开相机,让用户使用以下代码拍照: if ([UIImagePickerController isSourceTypeAvailable: UIImagePickerControllerSourceTypeCamera]) { UIImagePickerController *imagePicker = [[UIImagePickerController alloc] init]; imagePicker.delegate =
if ([UIImagePickerController isSourceTypeAvailable: UIImagePickerControllerSourceTypeCamera]) {
UIImagePickerController *imagePicker = [[UIImagePickerController alloc] init];
imagePicker.delegate = self;
imagePicker.sourceType =
UIImagePickerControllerSourceTypeCamera;
imagePicker.mediaTypes = @[(NSString *) kUTTypeImage];
imagePicker.allowsEditing = NO;
imagePicker.modalPresentationStyle = UIModalPresentationFullScreen;
[self presentViewController:imagePicker animated:YES completion:nil];
} else {
UIAlertView *alert = [[UIAlertView alloc]
initWithTitle: @"Camera failed to open"
message: @"Camera is not available"
delegate: nil
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alert show];
}
这将显示相机视图,以便用户可以拍照。我实现了处理取消和完成事件的方法,如下所示:
- (void)imagePickerControllerDidCancel:(UIImagePickerController *)picker {
[self dismissViewControllerAnimated:YES completion:nil];
}
- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info {
[self dismissViewControllerAnimated:YES completion:nil];
UIImage * image = [info objectForKey:UIImagePickerControllerEditedImage];
[photoView setImage:image];
[photoView setNeedsDisplay];
}
问题是,经过最后一个函数后,图像为零。起初dismissViewControllerAnimated位于函数的末尾,但在回答中解释了应该首先调用dismissViewControllerAnimated,并且应该在从info获取图像之前释放picker。我尝试将dismissViewControllerAnimated放在顶部,但因为我使用的是ARC,所以无法释放选择器
如何从信息中获取图像?试试以下方法:
UIImage *image = [info objectForKey:@"UIImagePickerControllerOriginalImage"];
// or UIImage *image = [info objectForKey:@"UIImagePickerControllerEditedImage"];
试试这个:
UIImage *image = [info objectForKey:@"UIImagePickerControllerOriginalImage"];
// or UIImage *image = [info objectForKey:@"UIImagePickerControllerEditedImage"];
您已设置
picker.allowsdediting=NO代码>在您的代码中。那么,为什么要检索已编辑的图像?它不会存在。无论如何,如果允许编辑,请使用以下命令:
photoView.image = info[UIImagePickerControllerEditedImage] ? info[UIImagePickerControllerEditedImage] : info[UIImagePickerControllerOriginalImage]
如果用户已编辑照片,photoView.image
将设置为已编辑的照片,否则将设置为原始照片
如果不允许编辑,只需使用UIImagePickerControllerOriginalImage
键检索图像即可。您已设置picker.AllowsEdit=NO代码>在您的代码中。那么,为什么要检索已编辑的图像?它不会存在。无论如何,如果允许编辑,请使用以下命令:
photoView.image = info[UIImagePickerControllerEditedImage] ? info[UIImagePickerControllerEditedImage] : info[UIImagePickerControllerOriginalImage]
如果用户已编辑照片,photoView.image
将设置为已编辑的照片,否则将设置为原始照片
如果不允许编辑,只需使用UIImagePickerControllerOriginalImage
键检索图像即可。选中此方法
(void) imagePickerController:(UIImagePickerController *)_picker didFinishPickingMediaWithInfo:(NSDictionary *)info {
NSLog(@"dictionary image info: %@",info );
}
在此方法中,打印字典并检查您是否获得UIImagePickerControllerMediaType和UIImagePickerControllerOriginalImage。
(在我的例子中,我得到的值如下UIImagePickerControllerMediaType=“public.image”;
UIImagePickerController原始图像=UIImage:0x1dd79520“)
现在,如果您正在获取UIImagePickerControllerOriginalImage的值,则将值保存在此UIImage中
现在用这个
UIImage *image = [info objectForKey:@"UIImagePickerControllerEditedImage"];
或
希望这会对您有所帮助。检查此方法
(void) imagePickerController:(UIImagePickerController *)_picker didFinishPickingMediaWithInfo:(NSDictionary *)info {
NSLog(@"dictionary image info: %@",info );
}
在此方法中,打印字典并检查您是否获得UIImagePickerControllerMediaType和UIImagePickerControllerOriginalImage。
(在我的例子中,我得到的值如下UIImagePickerControllerMediaType=“public.image”;
UIImagePickerController原始图像=UIImage:0x1dd79520“)
现在,如果您正在获取UIImagePickerControllerOriginalImage的值,则将值保存在此UIImage中
现在用这个
UIImage *image = [info objectForKey:@"UIImagePickerControllerEditedImage"];
或
希望这能对你有所帮助。这篇文章建议你在解雇后停止工作,以获得照片。你试过了吗?在关闭控制器之前使用你的代码获取一个图像。帖子建议你关闭后的块完成获取图像。您尝试过吗?在关闭控制器之前,使用您的代码获取图像。不允许编辑图像imagePicker.allowsdediting=NO代码>所以只需要检查原始图像。@selmad抱歉,没有收到您的信息。“你什么意思?”塞尔玛更新了我的答案。谢谢,谢谢,这很有效。这就是我从互联网上愚蠢地复制粘贴内容所得到的结果,它不允许编辑图像imagePicker.allowsdediting=NO代码>所以只需要检查原始图像。@selmad抱歉,没有收到您的信息。“你什么意思?”塞尔玛更新了我的答案。谢谢,谢谢,这很有效。这就是我愚蠢地从互联网上复制粘贴东西所得到的>