Mysql 错误1690(22003):BIGINT无符号值输出
错误1690(22003):中的BIGINT无符号值超出范围 (Mysql 错误1690(22003):BIGINT无符号值输出,mysql,Mysql,错误1690(22003):中的BIGINT无符号值超出范围 (dbadba\u IRIS\u警报ack\u ts- dbadba\u IRIS\u警报显示) 如何解决此错误?特别是在这种情况下,它是失败的 SELECT alertid, ackuid, severity, ticketid, From_unixtime(display_ts) AS Detection_Time,
dba
dba\u IRIS\u警报
ack\u ts
-
dba
dba\u IRIS\u警报
显示
)
如何解决此错误?特别是在这种情况下,它是失败的
SELECT alertid,
ackuid,
severity,
ticketid,
From_unixtime(display_ts) AS Detection_Time,
From_unixtime(ack_ts) AS Ack_Time,
Round(( ack_ts - display_ts ) / 60) AS MTTA_MINS,
IF (Round(( ack_ts - display_ts ) / 60) > 15, 1, 0) AS SLA_MISSED
FROM alerts_test
WHERE display_ts > Unix_timestamp(Now() - INTERVAL 26 day)
ORDER BY From_unixtime(display_ts);
样本数据
round((ack_ts-display_ts)/60) as MTTA_MINS,
IF ( round((ack_ts-display_ts)/60) > 15, 1, 0) as SLA_MISSED
发件人:
整数值之间的减法,其中一个为无符号类型,
默认情况下,生成未签名的结果。如果结果不是这样的话
已为负值,错误结果为:
+----------------------------------+-----------------+----------+-------------+---------------------+---------------------+-----------+------------+
| alertid | ackuid | severity | ticketid | Detection_Time | Ack_Time | MTTA_MINS | SLA_MISSED |
+----------------------------------+-----------------+----------+-------------+---------------------+---------------------+-----------+------------+
| xxxxxx | him | 5 | NULL | 2018-11-01 00:03:23 | 2018-11-01 00:06:18 | 3 | 0 |
| xxxxxx | him | 5 | NULL | 2018-11-01 00:11:08 | 2018-11-01 00:17:45 | 7 | 0 |
因此,我认为ack\u ts
和/或display\u ts
列(似乎表示Unix时间戳值)是使用CREATE TABLE
语句中的UNSIGNED
标志定义的(这很好,因为Unix时间戳值应该只有正值)
因此,您正在减去类型为UNSIGNED
的列,ack\u ts-display\u ts
的结果为负数。因此,您会遇到这样的情况:ack\u ts
<display\u ts
现在,有两种可能性:
确认
显示的情况李>
在这种情况下,您需要向查询中添加另一个WHERE
条件:
mysql> SET sql_mode = '';
Query OK, 0 rows affected (0.00 sec)
mysql> SELECT CAST(0 AS UNSIGNED) - 1;
ERROR 1690 (22003): BIGINT UNSIGNED value is out of range in '(cast(0 as unsigned) - 1)'
SELECT alertid,
ackuid,
severity,
ticketid,
From_unixtime(display_ts) AS Detection_Time,
From_unixtime(ack_ts) AS Ack_Time,
Round(( ack_ts - display_ts ) / 60) AS MTTA_MINS,
IF (Round(( ack_ts - display_ts ) / 60) > 15, 1, 0) AS SLA_MISSED
FROM alerts_test
WHERE display_ts > Unix_timestamp(Now() - INTERVAL 26 day) AND
ack_ts >= display_ts /* added one more condition to remove negative cases */
ORDER BY From_unixtime(display_ts);
另一个选项是将sql\u模式设置为使用。现在,您可以在设置模式后使用原始查询:
SELECT alertid,
ackuid,
severity,
ticketid,
From_unixtime(display_ts) AS Detection_Time,
From_unixtime(ack_ts) AS Ack_Time,
Round(( CAST(ack_ts AS SIGNED) - CAST(display_ts AS SIGNED) ) / 60) AS MTTA_MINS,
IF (Round(( CAST(ack_ts AS SIGNED) - CAST(display_ts AS SIGNED) ) / 60) > 15, 1, 0) AS SLA_MISSED
FROM alerts_test
WHERE display_ts > Unix_timestamp(Now() - INTERVAL 26 day)
ORDER BY From_unixtime(display_ts);
您可能无权全局更改此设置。因此,您可以在原始查询之前运行以下查询,以便仅对特定的客户端会话进行此更改
SET sql_mode = 'NO_UNSIGNED_SUBTRACTION';
有关设置sql_模式的更多详细信息,请查看此答案:有关此错误的任何帮助?请在问题中添加一些示例数据。或者摆弄一把小提琴:不看数据,很难弄清楚。你在问题中添加的不是样本数据。正如所示,列ack\u ts
和display\u ts
似乎存储Unix时间戳(秒)值。您能否将CREATE TABLE
语句结果添加到问题中。执行SHOW CREATE TABLE alerts\u test
并将此查询结果发布到问题中谢谢Madhur Bhaiya-第一个问题已解决我的问题。是确认(确认时间)应始终大于显示时间。
SET SESSION sql_mode = 'NO_UNSIGNED_SUBTRACTION';