Python 基于dataframe中单元格中的值对单元格应用颜色
工作代码Python 基于dataframe中单元格中的值对单元格应用颜色,python,pandas,matplotlib,seaborn,Python,Pandas,Matplotlib,Seaborn,工作代码 import pandas as pd import seaborn as sns import matplotlib as mpl import numpy as np from matplotlib import colors,cm from matplotlib import pyplot as plt filename = r'c:\Users\91956\Desktop\time_50.csv' df = pd.read_csv(filename,index_col=0)
import pandas as pd
import seaborn as sns
import matplotlib as mpl
import numpy as np
from matplotlib import colors,cm
from matplotlib import pyplot as plt
filename = r'c:\Users\91956\Desktop\time_50.csv'
df = pd.read_csv(filename,index_col=0)
select_col = df.columns[1:]
cmap = mpl.colors.LinearSegmentedColormap.from_list("", ["red","white", "green"])
def background_gradient(s, cmap='PuBu', low=0, high=0):
s = pd.to_numeric(s, errors='coerce') #<-- here, string will become nan.
m = s.min() #<---------- here
M = s.max() #<-----------here
rng = M - m
norm = colors.TwoSlopeNorm(vmin=m - (rng * low), vcenter=0., vmax=M + (rng * high))
normed = norm(s.values)
c = [colors.rgb2hex(x) for x in plt.cm.get_cmap(cmap)(normed)]
return ['background-color: %s' % color for color in c]
S = df.style.apply( background_gradient,
cmap=cmap,
low=0.5,
high=0.5,
subset= pd.IndexSlice[:, select_col],
axis=1
)
html = S.render()
with open("output.html","w") as fp:
fp.write(html)
将熊猫作为pd导入
导入seaborn作为sns
将matplotlib导入为mpl
将numpy作为np导入
从matplotlib导入颜色,cm
从matplotlib导入pyplot作为plt
filename=r'c:\Users\91956\Desktop\time\u 50.csv'
df=pd.read\u csv(文件名、索引\u col=0)
选择列[1:]
cmap=mpl.colors.LinearSegmentedColormap.from_列表(“,[“红色”,“白色”,“绿色])
def背景梯度(s,cmap='PuBu',低=0,高=0):
s=pd.to_numeric(s,errors='concurve')#这将有所帮助,也会有所帮助
要创建示例df,请执行以下操作:
import pandas as pd
import numpy as np
np.random.seed(24)
df = pd.DataFrame({'A': np.linspace(1, 10, 10)})
df = pd.concat([df, pd.DataFrame(np.random.randn(10, 4), columns=list('BCDE'))],
axis=1)
df.iloc[3, 3] = np.nan
df.iloc[0, 2] = np.nan
编辑2:
从matplotlib导入颜色
cmap=LinearSegmentedColormap。从_列表('rg',[“r”,“w”,“g”],N=256)
def背景梯度(s,cmap='PuBu',低=0,高=0):
s=pd.to_numeric(s,errors='concurve')
m=s.min()#问题是您的值范围的中值不是零。调用background\u gradient
时,尝试设置low,high
什么应该是high和low,以使零成为中间值,例如low=-5和high=5这样的值?它不起作用。我已经更新了我的答案@AniketPatil:检查它现在起作用了。正常值是多少(s.values)@AniketPatil:s是数据帧df的元素SPASSsubset=pd.indexlice[:,['B','C']]
检查编辑后的答案。也可以使用此列选择行,或仅选择要传递的列。可以将列名列表传递给子集。您可以根据您的需要修改此代码:)我正在使用的df如图所示,它包含str数据以及ticker列,我试图修改我的代码,但无法获得所需的输出,我已使用代码更新了问题,我正在使用非常完整的答案!美好的
from matplotlib import colors
cmap=LinearSegmentedColormap.from_list('rg',["r","w","g"], N=256)
def background_gradient(s, m, M, cmap='PuBu', low=0, high=0):
s = pd.to_numeric(s, errors='coerce') #<-- here, string will become nan.
print(s)
rng = M - m
norm = colors.DivergingNorm(vmin=m - (rng * low), vcenter=0., vmax=M + (rng * high))
normed = norm(s.values)
c = [colors.rgb2hex(x) for x in plt.cm.get_cmap(cmap)(normed)]
return ['background-color: %s' % color for color in c]
x = df.apply(pd.to_numeric, errors='coerce') #<--- here string will be converted to `NaN` so that I can find out the max and min value.
df.style.apply(background_gradient,
cmap=cmap,
m=x.min().min(),
M=x.max().max(),
low=0.5,
high=0.5, subset=pd.IndexSlice[:, ['B', 'C']]
)
df.style.apply(background_gradient,
cmap=cmap,
m=df.min().min(),
M=df.max().max(),
low=0.5,
high=0.5, subset=pd.IndexSlice[:, ['B', 'C']]
)
from matplotlib import colors
cmap=LinearSegmentedColormap.from_list('rg',["r","w","g"], N=256)
def background_gradient(s, cmap='PuBu', low=0, high=0):
s = pd.to_numeric(s, errors='coerce')
m = s.min() #<---------- here
M = s.max() #<-----------here
rng = M - m
norm = colors.DivergingNorm(vmin=m - (rng * low), vcenter=0., vmax=M + (rng * high))
normed = norm(s.values)
c = [colors.rgb2hex(x) for x in plt.cm.get_cmap(cmap)(normed)]
return ['background-color: %s' % color for color in c]
# x = df.apply(pd.to_numeric, errors='coerce')
df.style.apply(background_gradient,
cmap=cmap,
low=0.5,
high=0.5, subset=pd.IndexSlice[:, ['B', 'C', 'D']], axis=1
)