Python 使用'；或'；导致输出错误

我正在尝试制作一个刽子手游戏，在while循环中使用“or”来检查用户的输入。没有'or'循环可以正常工作，但是当我添加或使用另一个条件时，输出总是false

def Guess():
guess = input("Type 'guess' to guess a character or 'answer' to guess the answer:\n>")
while guess != 'guess':
    guess = input("That is an invalid input. Please type 'guess' to guess a character or 'answer' to guess the answer:\n>")

此代码正常工作-如果输入“猜测”，循环结束

def Guess():
guess = input("Type 'guess' to guess a character or 'answer' to guess the answer:\n>")
while guess != 'guess' or guess != 'answer':
    guess = input("That is an invalid input. Please type 'guess' to guess a character or 'answer' to guess the answer:\n>")

---

当我添加这个时，无论我输入什么，循环都会一直运行。你知道哪里出了问题吗？

猜测总是不等于这些值中的至少一个，所以你需要
和
，而不是
或
：

while guess != 'guess' and guess != 'answer':

如果您认为这令人困惑或难以阅读，请使用以下命令将其改写为：

while not (guess == 'guess' or guess == 'answer'):

一种更简短、可读性更强的解决方案是在
中使用
：

while guess not in ['guess', 'answer']:

guess
始终不等于这些值中的至少一个，因此您需要
和
，而不是
或
：

while guess != 'guess' and guess != 'answer':

如果您认为这令人困惑或难以阅读，请使用以下命令将其改写为：

while not (guess == 'guess' or guess == 'answer'):

一种更简短、可读性更强的解决方案是在
中使用
：

while guess not in ['guess', 'answer']: