python根据出现次数替换单词
我对python比较陌生。我想用一个不同的词替换出现两次以上的词。单词可以由多个单词组成。我希望它们被XYZ替换。例如:python根据出现次数替换单词,python,string,read-eval-print-loop,Python,String,Read Eval Print Loop,我对python比较陌生。我想用一个不同的词替换出现两次以上的词。单词可以由多个单词组成。我希望它们被XYZ替换。例如: ABC is a tall person. ABC likes sports. Sports are good for health. ABC is a gold medalist in many sports. ABC和sports应替换为XYZ。同样,上面的句子应该是: XYZ is a tall person. XYZ likes XYZ. XYZ are good
ABC is a tall person. ABC likes sports. Sports are good for health. ABC is a gold medalist in many sports.
ABC和sports应替换为XYZ。同样,上面的句子应该是:
XYZ is a tall person. XYZ likes XYZ. XYZ are good for health. XYZ is a gold medalist in many XYZ.
我使用了字典,能够计算出一个单词的出现次数。但是,我们无法正确地找到替代品。我想使用regex/for循环/数据结构(如列表/字典)来完成这项工作。是否有一个基于计数的替换函数可以提前完成此操作?因为您已经有了一个字典,您需要的是循环并检查单词是否出现两次或两次以上,然后运行string.replace(),用法示例:
s = ABC is a tall person. ABC likes sports. Sports are good for health. ABC is a gold medalist in many sports.
s.replace("ABC", "XYZ")
例如,在检查str.split()和str.replace()方法时,可以组合使用它们
b=a.split(' ',1)
if(b.count(b[i])) > 1:
b.replace(b[i],'XYZ')
请分享你一直在做的工作的代码。将代码中“无法正确替换”的部分张贴出来。这将帮助我们找出你的错误所在。