Ruby on rails rake db:尝试填充外键字段时出现种子抛出属性未找到错误

我正在尝试在我的应用程序中建立关系，以便：

a broadcast has 0..1 post and 0..1 jobs

我已经研究了

属于

并且

有一个

并且我已经尝试实现了这些，我在我的应用程序中有其他这样做的例子，这些例子都很有效，所以我无法理解为什么没有

以下是我的

帖子

和

作业

表格

class CreateJobs < ActiveRecord::Migration
  def change
    create_table :jobs do |t|
      t.text :title, null: :no #Must have a title
      t.string :content, default: 'No content specified'
      t.references :broadcast, null: :no, index: true  # Must have been broadcast
      t.timestamps
    end
  end
end

class CreatePosts < ActiveRecord::Migration
  def change
    create_table :posts do |t|
      t.text :title, null: :no #Must have a title
      t.string :content, default: 'No content specified'
      t.references :broadcast, null: :no, index: true  # Must have been broadcast
      t.timestamps  # Created at will double up as post date
    end
  end
end

这是

db:migrate

create_table "broadcasts", force: true do |t|
    t.text     "title"
    t.text     "content"
    t.boolean  "jobs",       default: false
    t.boolean  "general",    default: false
    t.integer  "user_id"
    t.datetime "created_at"
    t.datetime "updated_at"
  end

add_index "jobs", ["broadcast_id"], name: "index_jobs_on_broadcast_id"

  create_table "posts", force: true do |t|
    t.text     "title"
    t.string   "content",      default: "No content specified"
    t.integer  "broadcast_id"
    t.datetime "created_at"
    t.datetime "updated_at"
  end

  add_index "posts", ["broadcast_id"], name: "index_posts_on_broadcast_id"

  create_table "user_details", force: true do |t|
    t.string  "login",            limit: 40
    t.string  "salt",             limit: 40
    t.string  "crypted_password", limit: 40
    t.integer "user_id"
  end

这是

seeds.rb

文件

broadcast = Broadcast.create!(title: 'seed title 1 Broadcast', content: 'seeded Broadcast', jobs: true, general: true,
                              user: user)

 Post.create!(title: 'seed title 1', content: "#{broadcast.content}", broadcast: broadcast)

 broadcast2 = Broadcast.create!(title: 'seed title 2 Broadcast', content: 'Another seeded broadcast', general: true,
                              user: user)

 broadcast3 = Broadcast.create!(title: 'seed title 3 Broadcast', content: 'Another seeded broadcast', jobs: true,
                                                           user: user)

 Post.create!(title: 'seed title 2', content: "#{broadcast2.content}", broadcast: broadcast2)

 Job.create!(title: 'seed title 1 job', content: "#{broadcast.content}", broadcast: broadcast2)
 Job.create!(title: 'seed title 2 job', content: "#{broadcast2.content}", broadcast: broadcast3)

这是从rake db:seed抛出的错误消息

我已经在SQL资源管理器中检查了数据库，并且表确实存在，我不确定为什么这个错误会持续出现

rake aborted!
ActiveRecord::UnknownAttributeError: unknown attribute: broadcast

在这一行：

 Post.create!(title: 'seed title 1', content: "#{broadcast.content}", broadcast: broadcast)

如果你需要更多的代码，就问我。毫无疑问，我遗漏了一些明显的东西，但这样做在我的其他项目中起了作用

谢谢，

---

克里斯。

你的代码应该行得通。.我不知道为什么协会不按你的方式接受

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对象。应该可以。你的

广播

迁移在哪里。。我的电脑出了故障，我重置了我的机器，现在它可以工作了。很好。。很好！！。。。。。。。。。。

 Post.create!(title: 'seed title 1', content: "#{broadcast.content}", broadcast: broadcast)