Scala 如何模拟为不同调用返回不同值的uuid生成器?
我有一个uuid生成器,如:Scala 如何模拟为不同调用返回不同值的uuid生成器?,scala,mocking,mockito,specs2,Scala,Mocking,Mockito,Specs2,我有一个uuid生成器,如: class NewUuid { def apply: String = UUID.randomUUID().toString.replace("-", "") } 其他类可以使用它: class Dialog { val newUuid = new NewUuid def newButtons(): Seq[Button] = Seq(new Button(newUuid()), new Button(newUuid())) } 现在我想
class NewUuid {
def apply: String = UUID.randomUUID().toString.replace("-", "")
}
其他类可以使用它:
class Dialog {
val newUuid = new NewUuid
def newButtons(): Seq[Button] = Seq(new Button(newUuid()), new Button(newUuid()))
}
现在我想测试对话框
并模拟newUuid
:
val dialog = new Dialog {
val newUuid = mock[NewUuid]
newUuid.apply returns "uuid1"
}
dialog.newButtons().map(_.text) === Seq("uuid1", "uuid1")
您可以看到返回的uuid总是uuid1
是否可以让newUuid
为不同的调用返回不同的值?e、 g.第一个调用返回uuid1
,第二个调用返回uuid2
,以此类推
newUuid.apply returns "uudi1" thenReturns "uuid2"
使用迭代器生成UUID
def newUuid() = UUID.randomUUID().toString.replace("-", "")
val defaultUuidSource = Iterator continually newUuid()
class Dialog(uuids: Iterator[String] = defaultUuidSource) {
def newButtons() = Seq(
Button(uuids.next()),
Button(uuids.next())
)
}
然后提供一个不同的测试:
val testUuidSource = Iterator from 1 map {"uuid" + _}
new Dialog(testUuidSource)