Sql server 参数化数据透视表

我们有三张桌子

tid_颜色-参数化表

--------------------------
ID         ColorDescription
--------------------------
1          Green
2          Yellow
3          Red
-------------------------

--------------------------
ID         CARDescription
-------------------------
1          Car X
2          Car Y
3          Car Z
-------------------------- 

tid_车辆-参数化表

--------------------------
ID         ColorDescription
--------------------------
1          Green
2          Yellow
3          Red
-------------------------

--------------------------
ID         CARDescription
-------------------------
1          Car X
2          Car Y
3          Car Z
-------------------------- 

表(车主)(汽车)

------------------------------------------------
ID         CarID       ColorID      Owner
------------------------------------------------
1           1             1           John
2           1             2           Mary
3           1             3           Mary  
4           1             3           Giovanni     
5           2             2           Mary
6           3             1           Carl
7           1             1           Hawking
8           1             1           Fanny 
------------------------------------------------

CarID是tid_汽车的外键

ColorId是tid_颜色的外键

如果我们编码：

SELECT tcar.CarDescription, tco.ColorDescription, Count(*) as Total
FROM table_owners_cars tocar
LEFT JOIN tid_color tco ON tco.Id = tocar.ColorId
LEFT JOIN tid_Car tcar ON tcar.Id = tocar.CarId
GROUP BY CarDescription, ColorDescription 

其结果如下：

Id CarDescription     ColorDescription  Total
1       CarX               Green          3
2       CarX               Yellow         1
3       CarX               Red            1
4       CarY               Yellow         1
5       CarZ               Green          1

但我想在标题中的颜色，所以我有代码作为

SELECT CarId, [1] as 'Green', [2] as 'Yellow', [3] as 'Red', [1]+[2]+[3] as 'total' 
FROM
(SELECT CarID, colorId
 FROM table_owners_cars tocar
 LEFT JOIN tid_car tc  ON tocar.CarId=tc.Id) p 
PIVOT
( 
 COUNT (ColorId)
 FOR ColorId IN ( [1], [2], [3]) 
) AS pvt

使用以下SQL生成的表：

  ---------------------------------------------
   Id        Car     Green Yellow  Red    Total
   ---------------------------------------------
    1         1        3     1     1       5
    2         2        0     1     0       1                
    3         3        1     0     0       1                   
   ---------------------------------------------

它无法将汽车的描述（CarX、CarY、CarZ）放在汽车列中。。。而不是前面代码中的第一个选择，我尝试将其作为

选择tc.CardDescription，[1]为“绿色”；[2]为“黄色”；[3]为“红色”；[1]+[2]+[3]为“总计”

然后它抛出

无法绑定多部分标识符“tc.CardDescription”

我想要卡片说明，而不是上表中显示的ID。我希望得到的表格如下

我想准确地按如下方式旋转：

   ---------------------------------------------
   Id        Car     Green Yellow  Red    Total
   ---------------------------------------------
    1       CarX        3     1     1       5
    2       CarY        0     1     0       1                
    3       CarZ        1     0     0       1                   
   ---------------------------------------------

---

如何做到这一点？谢谢

您可以连接到数据透视结果：

 SELECT pvt.CarID, tc.Description AS Car, [1] as 'Green', [2] as 'Yellow', [3] as 'Red', [1]+[2]+[3] as 'total' 
    FROM
    (SELECT CarID, colorId
     FROM table_owners_cars tocar
     ) p 
    PIVOT
    ( 
     COUNT (ColorId)
     FOR ColorId IN ( [1], [2], [3]) 
    ) AS pvt
    INNER JOIN tid_car tc  ON pvt.CarId=tc.Id