String 如何在lua中找到字符串的一部分,并将其拆分为3部分?(之前、匹配、之后)
假设我有这根绳子,我想把蓝色分开String 如何在lua中找到字符串的一部分,并将其拆分为3部分?(之前、匹配、之后),string,split,lua,coronasdk,String,Split,Lua,Coronasdk,假设我有这根绳子,我想把蓝色分开 local str = "The mouse walked by the blue cheese" 这样做 local pre = "The mouse walked by the " local matched = "blue" local post = " cheese" 有什么建议吗?我找了一段时间,感觉被卡住了 我试过这个,它适用于英语,但似乎不适用于阿拉伯语: function split(string, delimiter)
local str = "The mouse walked by the blue cheese"
这样做
local pre = "The mouse walked by the "
local matched = "blue"
local post = " cheese"
有什么建议吗?我找了一段时间,感觉被卡住了
我试过这个,它适用于英语,但似乎不适用于阿拉伯语:
function split(string, delimiter)
local result = { }
local from = 1
local delim_from, delim_to = string.find( string, delimiter, from )
while delim_from do
table.insert( result, string.sub( string, from , delim_from-1 ) )
from = delim_to + 1
delim_from, delim_to = string.find( string, delimiter, from )
end
table.insert( result, string.sub( string, from ) )
return result
end
local myStr = "The mouse walked by the blue cheese"
sep = split(myStr, "blue")
print("part1 1: "..sep[1])
print("part2 2: "..sep[2])
编辑===================================================
请告诉我如果有多个目标词要拆分,该怎么办
比如说
local myStr = "the mouse ate the cheese, the mouse ate the cheese!, lot of cheese there !"
这里的问题是它将其拆分为多个,需要的是
before=老鼠吃了after=老鼠吃了奶酪!,
那里有很多奶酪
这是我做的,它适用于英语,但不适用于阿拉伯语
function split4(pString, pPattern)
local didFind = 0
if string.find(pString,".") then
pString = string.gsub(pString,"%.","'.'")
end
if pPattern == "." then
pPattern = "'.'"
end
local Table = {} -- NOTE: use {n = 0} in Lua-5.0
local FinalTable = {}
local fpat = "(.-)" .. pPattern
local last_end = 1
local s, e, cap = pString:find(fpat, 1)
while s do
if s ~= 1 or cap ~= "" then
print("Found")
table.insert(Table,cap)
didFind = didFind + 1
end
last_end = e+1
s, e, cap = pString:find(fpat, last_end)
end
if last_end <= #pString then
print("Found NOT")
cap = pString:sub(last_end)
table.insert(Table, cap)
end
print(#Table)
print("totalDidFind "..didFind)
FinalTable[1] = Table[1]
if (didFind > 2) then
local endString = ""
for z = 2 , didFind do
endString = endString..Table[z]..pPattern
end
FinalTable[2] = endString
end
totalDidFind = 0
return FinalTable
end
您可以将string.match用于:
现在,您的拆分函数非常简单:
function split(str, match)
return str:match('^(.-)'..match..'(.*)$') -- Return two resulsts, but not table
end
附言:也许,你想在文本中找到多个匹配项?在这种情况下,请编辑您的问题。您可以使用string.match with:
现在,您的拆分函数非常简单:
function split(str, match)
return str:match('^(.-)'..match..'(.*)$') -- Return two resulsts, but not table
end
附言:也许,你想在文本中找到多个匹配项?在这种情况下,请编辑您的问题。Lua没有正则表达式,而是。类似,但应注意区别。请看一下编辑后的版本好吗?@Deyaelden很抱歉反应极为延迟,但将first*替换为-会在第一次出现时发生此拆分,而不是最后一次。Lua没有正则表达式,而是。类似,但区别应该注意。你能看一下编辑过的版本吗?@Deyaelden很抱歉反应非常延迟,但将first*替换为-会在第一次出现时导致此拆分,而不是最后一次。