Php 如何将变量作为cURL数组中的url参数传递给CURLOPT_url
我有这段php代码,它使用cURL解析来自decision.com的xml提要。我正在将服务器信息(如远程地址和HTTP用户代理)传递到url的参数中,但没有传递它们 检查下面代码的这一部分<代码>'.geogoECKIP($\u服务器['REMOTE\u ADDR'])。 这是正确的方法。只是不确定当它是CURLOPT_URL=> 当使用cURL中的数组(如下面CURLOPT_url=>中的函数)时,将这些服务器代码段传递到url参数的正确方法是什么 下面的php代码是我页面上的全部代码,因此您可以更好地了解正在发生的事情 我试图在用户到达我的网站以显示本地区的工作列表时检测他们所在的城市和州。php代码可以工作,我可以在网页上回显城市状态,但它没有将相同的信息传递给数组中的函数curl_request()。请帮忙Php 如何将变量作为cURL数组中的url参数传递给CURLOPT_url,php,arrays,variables,curl,url-parameters,Php,Arrays,Variables,Curl,Url Parameters,我有这段php代码,它使用cURL解析来自decision.com的xml提要。我正在将服务器信息(如远程地址和HTTP用户代理)传递到url的参数中,但没有传递它们 检查下面代码的这一部分'.geogoECKIP($\u服务器['REMOTE\u ADDR'])。 这是正确的方法。只是不确定当它是CURLOPT_URL=> 当使用cURL中的数组(如下面CURLOPT_url=>中的函数)时,将这些服务器代码段传递到url参数的正确方法是什么 下面的php代码是我页面上的全部代码,因此您可以更
<?php
// Convert IP into city state country (Geo Location function)
function geoCheckIP($ip){
if(!filter_var($ip, FILTER_VALIDATE_IP))
{
throw new InvalidArgumentException("IP is not valid");
}
$response=@file_get_contents('http://www.netip.de/search?query='.$ip);
if (empty($response))
{
throw new InvalidArgumentException("Error contacting Geo-IP-Server");
}
$patterns=array();
$patterns["domain"] = '#Domain: (.*?) #i';
$patterns["country"] = '#Country: (.*?) #i';
$patterns["state"] = '#State/Region: (.*?)<br#i';
$patterns["town"] = '#City: (.*?)<br#i';
$ipInfo=array();
foreach ($patterns as $key => $pattern)
{
$ipInfo[$key] = preg_match($pattern,$response,$value) && !empty($value[1]) ? $value[1] : 'not found';
}
/*I've included the substr function for Country to exclude the abbreviation (UK, US, etc..)
To use the country abbreviation, simply modify the substr statement to:
substr($ipInfo["country"], 0, 3)
*/
$ipdata = $ipInfo["town"]. ", ".$ipInfo["state"]/*.", ".substr($ipInfo["country"], 4)*/;
return $ipdata;
}
// Indeed php function
function curl_request(){
$curl = curl_init();
curl_setopt_array($curl, array(
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_URL => 'http://api.indeed.com/ads/apisearch?publisher=&q=computer+repair&l='.geoCheckIP($_SERVER['REMOTE_ADDR']).'&sort=&radius=25&st=&jt=&start=&limit=&fromage=&highlight=1&filter=1&latlong=0&co=us&chnl=computer+help+wanted&userip='.$_SERVER['REMOTE_ADDR'].'&useragent='.$_SERVER['HTTP_USER_AGENT'].'&v=2',
));
$resp = curl_exec($curl);
curl_close($curl);
return $resp;
}
function xmlToArray($input, $callback = null, $recurse = false) {
$data = ((!$recurse) && is_string($input))? simplexml_load_string($input, 'SimpleXMLElement', LIBXML_NOCDATA): $input;
if ($data instanceof SimpleXMLElement) $data = (array) $data;
if (is_array($data)) foreach ($data as &$item) $item = xmlToArray($item, $callback, true);
return (!is_array($data) && is_callable($callback))? call_user_func($callback, $data): $data;
}
?>
这不起作用
CURLOPT_URL => 'http://api.indeed.com/ads/apisearch?publisher=&q=computer+repair&l='.geoCheckIP($_SERVER['REMOTE_ADDR']).'&sort=&radius=25&st=&jt=&start=&limit=&fromage=&highlight=1&filter=1&latlong=0&co=us&chnl=computer+help+wanted&userip='.$_SERVER['REMOTE_ADDR'].'&useragent='.$_SERVER['HTTP_USER_AGENT'].'&v=2',
这里有一个恰当的解释: 您可以从那里获取语法并将其与curl一起使用 有助于以数组形式创建url参数的函数示例:
public function createArrParam($key, $values) {
return implode('&' . $key . '[]=', array_map('urlencode', $values));
}
之后,您只需获取url并将其与结果连接起来:
$values = array(1, 2, 3, 4, 5);
$url = 'http://stackoverflow.com?bla=blupp' . createArrParam('myArr', $values);
就这样,
function curl_request()
{
// Get cURL resource
$curl = curl_init();
// Set some options
$curl_config = array(
CURLOPT_URL => 'http://api.indeed.com/ads/apisearch',
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_POSTFIELDS => array(
"publisher" => "",
"q" => "computer+repair",
"l" => $user_location,
"sort" => "",
"radius" => 25,
"st" => "",
"jt" => "",
"start" => "",
"limit" => "",
"fromage" => "",
"highlight" => 1,
"filter" => 1,
"latlong" => 0,
"co" => "us",
"chnl" => "computer+help+wanted",
"userip" => $user_ip,
"useragent" => $user_agent,
"v" => 2
)
);
curl_setopt_array($curl, $curl_config);
// Send the request & save response to $resp
$resp = curl_exec($curl);
// Close request to clear up some resources
curl_close($curl);
return $resp;
}
编辑
这对你不起作用的原因可能有1到2个
1。您没有传入在函数外部定义的变量(我在第一个答案中也没有)。
要解决此问题,您需要在函数定义中以及调用函数时将它们像sofunction curl\u request($user\u ip、$user\u agent、$user\u location)
一样传入。或者更改在URL字符串中输入它们的方式
curl_setopt_array($curl, array(
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_URL => 'http://api.indeed.com/ads/apisearch?publisher=&q=computer+repair&l='.geoCheckIP($_SERVER['HTTP_USER_AGENT']).'&sort=&radius=25&st=&jt=&start=&limit=&fromage=&highlight=1&filter=1&latlong=0&co=us&chnl=computer+help+wanted&userip='.$$_SERVER['REMOTE_ADDR'].'&useragent='.$_SERVER['HTTP_USER_AGENT'].'&v=2'
));
$\u SERVER
是一个全局变量,因此它不需要作为参数传递到函数中,就可以像这样工作
2.您调用的api不接受
POST
请求,仅请求GET
,在这种情况下,我的第一个示例不起作用,而您的第一个示例应该起作用,只要您通过第1点中概述的变量。就不需要使用cURL,而且加载速度非常慢。下面是一种非常简单的方法,可以在纯php中获得xml文档的结果,并使用GeogoEckip函数对其进行充分处理
<?php
// Convert IP into city state country (Geo Location function)
function geoCheckIP($ip){
if(!filter_var($ip, FILTER_VALIDATE_IP))
{
throw new InvalidArgumentException('IP is not valid');
}
$response=@file_get_contents('http://www.netip.de/search?query='.$ip);
if (empty($response))
{
throw new InvalidArgumentException('Error contacting Geo-IP-Server');
}
$patterns=array();
$patterns["domain"] = '#Domain: (.*?) #i';
$patterns["country"] = '#Country: (.*?) #i';
$patterns["state"] = '#State/Region: (.*?)<br#i';
$patterns["town"] = '#City: (.*?)<br#i';
$ipInfo=array();
foreach ($patterns as $key => $pattern)
{
$ipInfo[$key] = preg_match($pattern,$response,$value) && !empty($value[1]) ? $value[1] : 'not found';
}
/*I've included the substr function for Country to exclude the abbreviation (UK, US, etc..)
To use the country abbreviation, simply modify the substr statement to:
substr($ipInfo["country"], 0, 3)
*/
$ipdata = $ipInfo["town"]. ", ".$ipInfo["state"]/*.", ".substr($ipInfo["country"], 4)*/;
return $ipdata;
}
// Indeed.com API URL parameters
$url = 'http://api.indeed.com/ads/apisearch'.'?';
$publisher = 'YOUR PUB NUMBER GOES HERE';
$q = 'title:(java or java+programmer or java+programming)';
$l = geoCheckIP($_SERVER['REMOTE_ADDR']);
$sort = 'date';
$radius = '20';
$st = '';
$jt = '';
$start = '0';
$limit = '25';
$fromage = '';
$highlight = '0';
$filter = '1';
$latlong = '0';
$co = 'us';
$chnl = 'YOUR CHANNEL NAME';
$userip = $_SERVER['REMOTE_ADDR'];
$useragent = isset($_SERVER['HTTP_USER_AGENT']) ? ($_SERVER['HTTP_USER_AGENT']) : 'unknown';
$v = '2';
这应该是一个评论,而不是回答我会回答的…;)!谢谢@hindsots我会扩展它的@PLM57非常感谢您将php中的代码整合到我上面的代码中。我很想看看这将如何工作。我试图在url参数中传递的变量是$user\u ip和$user\u agent以及$user\u location。我不知道在这段代码中该放在哪里。请看我的编辑,我添加了一些变量,希望这会告诉你如何添加其余的变量。参数名在数组的左侧,该参数的值在右侧。更新以添加所有参数,并更改url(如示例中所示)似乎不起作用。我该如何回显测试结果呢?抱歉,我不小心删除了curl\u setopt\u数组($curl,$curl\u config)代码>行。回到现在,再试一次。如果您将URL的geogoceckip()
部分更改为静态文本,是否有效???@Novocaine88是。当我将此部分更改为“”时,它会起作用。GeogoEckip($\u SERVER['REMOTE\u ADDR'])。
转换为静态文本,如纽约州纽约市或静态邮政编码也会起作用10001
。你还能帮我吗?我唯一的建议是你的geogoceckip
功能可能工作不正常。如果您自己使用它,它是否会像预期的那样返回字符串?考虑到用静态文本切换该函数,我怀疑它不起作用。@Novocaine88是的,GeogoEckip工作正常。我毕竟没有使用这个代码。我现在正在使用一种不用curl的更好的代码。curl代码有问题,加载速度也非常慢。
curl_setopt_array($curl, array(
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_URL => 'http://api.indeed.com/ads/apisearch?publisher=&q=computer+repair&l='.geoCheckIP($_SERVER['HTTP_USER_AGENT']).'&sort=&radius=25&st=&jt=&start=&limit=&fromage=&highlight=1&filter=1&latlong=0&co=us&chnl=computer+help+wanted&userip='.$$_SERVER['REMOTE_ADDR'].'&useragent='.$_SERVER['HTTP_USER_AGENT'].'&v=2'
));
<?php
// Convert IP into city state country (Geo Location function)
function geoCheckIP($ip){
if(!filter_var($ip, FILTER_VALIDATE_IP))
{
throw new InvalidArgumentException('IP is not valid');
}
$response=@file_get_contents('http://www.netip.de/search?query='.$ip);
if (empty($response))
{
throw new InvalidArgumentException('Error contacting Geo-IP-Server');
}
$patterns=array();
$patterns["domain"] = '#Domain: (.*?) #i';
$patterns["country"] = '#Country: (.*?) #i';
$patterns["state"] = '#State/Region: (.*?)<br#i';
$patterns["town"] = '#City: (.*?)<br#i';
$ipInfo=array();
foreach ($patterns as $key => $pattern)
{
$ipInfo[$key] = preg_match($pattern,$response,$value) && !empty($value[1]) ? $value[1] : 'not found';
}
/*I've included the substr function for Country to exclude the abbreviation (UK, US, etc..)
To use the country abbreviation, simply modify the substr statement to:
substr($ipInfo["country"], 0, 3)
*/
$ipdata = $ipInfo["town"]. ", ".$ipInfo["state"]/*.", ".substr($ipInfo["country"], 4)*/;
return $ipdata;
}
// Indeed.com API URL parameters
$url = 'http://api.indeed.com/ads/apisearch'.'?';
$publisher = 'YOUR PUB NUMBER GOES HERE';
$q = 'title:(java or java+programmer or java+programming)';
$l = geoCheckIP($_SERVER['REMOTE_ADDR']);
$sort = 'date';
$radius = '20';
$st = '';
$jt = '';
$start = '0';
$limit = '25';
$fromage = '';
$highlight = '0';
$filter = '1';
$latlong = '0';
$co = 'us';
$chnl = 'YOUR CHANNEL NAME';
$userip = $_SERVER['REMOTE_ADDR'];
$useragent = isset($_SERVER['HTTP_USER_AGENT']) ? ($_SERVER['HTTP_USER_AGENT']) : 'unknown';
$v = '2';
<!-- BEGIN INDEED ORDERED LIST-->
<ol class="jobs">
<?php
$xml = simplexml_load_file($url."publisher=".$publisher."&q=".$q."&l=".$l."&sort=".$sort."&radius=".$radius."&st=".$st."&jt=".$jt."&start=".$start."&limit=".$limit."&fromage=".$fromage."&highlight=".$highlight."&filter=".$filter."&latlong=".$latlong."&co=".$co."&chnl=".$chnl."&userip=".$userip."&useragent=".$useragent."&v=".$v);
foreach($xml->results->result as $result) { ?>
<li class="job">
<div id="jobtitle"><strong><a onmousedown="<?php echo $result->onmousedown;?>" rel="nofollow" href="<?php echo $result->url;?>" target="_blank"><?php echo $result->jobtitle;?></a></strong></div>
<div id="company"><?php echo $result->company;?></div>
<div id="snippet">
<?php echo $result->snippet;?>
</div>
<div id="location"><strong>Location:</strong> <?php echo $result->formattedLocationFull;?></div>
<div id="date"><span class="posted">Posted <?php echo $result->formattedRelativeTime;?></span></div>
</li>
<?php } ?>
</ol>
<!-- END INDEED ORDERED LIST -->