PHP preg_match-如果匹配，则返回结果？

我试图显示屏幕的超链接，但仅当相应的ID记录在字符串中时

<?php
function check($i, $s) {
    if (preg_match('/'.$i.'/',$test)) echo $s;
}

$test = "000,001,002,003,004,005";

check("001","<a href=''>This is in the test string - 001</a>");
check("003","<a href=''>This is in the test string - 003</a>");
check("006","<a href=''>This is in the test string - 006</a>");
check("020","<a href=''>This is in the test string - 020</a>");
?>

所需的输出将是：

<a href=''>This is in the test string - 001</a>
<a href=''>This is in the test string - 003</a>

因为它们是与字符串中的值唯一匹配的两个

这不管用。。你能告诉我为什么以及如何让它工作吗

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感谢您没有在函数中定义变量$test。你可以做个比方

<?php
function check($i, $s, $test) {
    if (preg_match('/'.$i.'/',$test)) echo $s;
}

$test = "000,001,002,003,004,005";

check("001","<a href=''>This is in the test string - 001</a>", $test);
check("003","<a href=''>This is in the test string - 003</a>", $test);
check("006","<a href=''>This is in the test string - 006</a>", $test);
check("020","<a href=''>This is in the test string - 020</a>", $test);
?>

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为什么您没有为通知启用错误报告？所有这些的目标是什么？谢谢-完全错过了打开错误报告的机会！

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