Python 3.x PythonPandas:按行而不是按整个数据帧设置引导置信限
我想做的是,不管行数多少,按行获取引导置信限,并从输出中生成一个新的数据帧。我目前可以对整个数据帧执行此操作,但不能按行执行。我在实际程序中的数据与下面的数据相似:Python 3.x PythonPandas:按行而不是按整个数据帧设置引导置信限,python-3.x,pandas,statistics-bootstrap,scikits,Python 3.x,Pandas,Statistics Bootstrap,Scikits,我想做的是,不管行数多少,按行获取引导置信限,并从输出中生成一个新的数据帧。我目前可以对整个数据帧执行此操作,但不能按行执行。我在实际程序中的数据与下面的数据相似: 0 1 2 0 1 2 3 1 4 1 4 2 1 2 3 3 4 1 4 我希望新的数据帧看起来像这样,具有置信下限和置信上限: 0 1 0 1 2 1 1 5.5 2 1 4.5 3 1 4.2 当前
0 1 2
0 1 2 3
1 4 1 4
2 1 2 3
3 4 1 4
我希望新的数据帧看起来像这样,具有置信下限和置信上限:
0 1
0 1 2
1 1 5.5
2 1 4.5
3 1 4.2
当前生成的输出如下所示:
0 1
0 2.0 2.75
下面的python 3代码生成一个模拟数据帧,并为整个数据帧生成引导置信限。结果是一个新的数据帧,只有2个值,一个置信上限和一个置信下限,而不是每行2个1的4组
import pandas as pd
import numpy as np
import scikits.bootstrap as sci
zz = pd.DataFrame([[[1,2],[2,3],[3,6]],[[4,2],[1,4],[4,6]],
[[1,2],[2,3],[3,6]],[[4,2],[1,4],[4,6]]])
print(zz)
x= zz.dtypes
print(x)
a = pd.DataFrame(np.array(zz.values.tolist())[:, :, 0],zz.index, zz.columns)
print(a)
b = sci.ci(a)
b = pd.DataFrame(b)
b = b.T
print(b)
感谢您的帮助。下面是我最后想出的按行创建引导ci的答案
import pandas as pd
import numpy as np
import numpy.random as npr
zz = pd.DataFrame([[[1,2],[2,3],[3,6]],[[4,2],[1,4],[4,6]],
[[1,2],[2,3],[3,6]],[[4,2],[1,4],[4,6]]])
x= zz.dtypes
a = pd.DataFrame(np.array(zz.values.tolist())[:, :, 0],zz.index, zz.columns)
print(a)
def bootstrap(data, num_samples, statistic, alpha):
n = len(data)
idx = npr.randint(0, n, (num_samples, n))
samples = data[idx]
stat = np.sort(statistic(samples, 1))
return (stat[int((alpha/2.0)*num_samples)],
stat[int((1-alpha/2.0)*num_samples)])
cc = list(a.index.values) # informs generator of the number of rows
def bootbyrow(cc):
for xx in range(1):
xx = list(a.index.values)
for xx in range(len(cc)):
k = a.apply(lambda y: y[xx])
k = k.values
for xx in range(1):
kk = list(bootstrap(k,10000,np.mean,0.05))
yield list(kk)
abc = pd.DataFrame(list(bootbyrow(cc))) #bootstrap ci by row
# the next 4 just show that its working correctly
a0 = bootstrap((a.loc[0,].values),10000,np.mean,0.05)
a1 = bootstrap((a.loc[1,].values),10000,np.mean,0.05)
a2 = bootstrap((a.loc[2,].values),10000,np.mean,0.05)
a3 = bootstrap((a.loc[3,].values),10000,np.mean,0.05)
print(abc)
print(a0)
print(a1)
print(a2)
print(a3)
bootstrap的工作原理是假设数据样本是按行而不是按列排列的。如果想要相反的行为,只需使用转置和不合并列的statfunction
import pandas as pd
import numpy as np
import scikits.bootstrap as sci
zz = pd.DataFrame([[[1,2],[2,3],[3,6]],[[4,2],[1,4],[4,6]],
[[1,2],[2,3],[3,6]],[[4,2],[1,4],[4,6]]])
print(zz)
x= zz.dtypes
print(x)
a = pd.DataFrame(np.array(zz.values.tolist())[:, :, 0],zz.index, zz.columns)
print(a)
b = sci.ci(a.T, statfunction=lambda x: np.average(x, axis=0))
print(b.T)