如何获得用户'；python3的int和float中的s输入

如何为python3获取用户的int和float输入

显然是编了一个计算器，但我希望用户的输入是int和float，不仅仅是int或float，而是两者。这基本上就是我所关心的，更改int以获得int和float。遗憾的是，Java使用了double

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我建议您将输入作为一个浮点数。这样，如果用户输入浮点值，您就可以支持它

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如果用户输入一个int，它也将被支持。如果出于某种原因，您想检查输入是否为int，您可以只检查数字在小数点后是否有0。

使用字符串构造函数将输入作为decimal.decimal以避免浮点精度损失。Decimal可以表示任意精度，包括整数，并且始终返回计算器期望的值

def calculator():
    def add(x, y):
        return x + y

    def sub(x, y):
        return x - y

    def mul(x, y):
        return x * y

    def div(x, y):
        return x / y

    def power(x, y):
        return x ** y

    def modulus(x, y):
        return x % y

    print(""" -- Select Operation --
    1. Addition
    2. Subtraction
    3. Multiplication
    4. Division
    5. Power
    6. Modulus
    """)
    from decimal import Decimal
    choice = input("Enter 1 or 2 or 3 or 4 or 5 or 6 from the Select Operation >> ")
    while choice not in ('1', '2', '3', '4', '5', '6'):
        choice = input("Invalid Input! Please Enter 1 or 2 or 3 or 4 or 5 or 6 from the Select Operation >> ")
    print("\n")
    print("============================================================")
    print("Gathering data...")
    # How to make user input in both int and float not int alone?
    num1 = Decimal(input("Enter First number >> "))
    num2 = Decimal(input("Enter Second number >> "))

    if choice == '1':
        print(num1, "+", num2, "=", str(add(num1, num2)))
    elif choice == '2':
        print(num1, "-", num2, "=", str(sub(num1, num2)))
    elif choice == '3':
        print(num1, "*", num2, "=", str(mul(num1, num2)))
    elif choice == '4':
        print(num1, "/", num2, "=", str(div(num1, num2)))
    elif choice == '5':
        print(num1, "^", num2, "=", str(power(num1, num2)))
    elif choice == '6':
        print(num1, "%", num2, "=", str(modulus(num1, num2)))
    repeat_cal()

def repeat_cal():
    print("Do you want to Select Operation again")
    choose_again = input("Enter Y for YES or N for NO>> ")
    if choose_again.upper() == 'Y':
        calculator()
    elif choose_again.upper() == 'N':
        print("-----------------Good Bye!---------------------------")
        exit()
    else:
        repeat_cal()

calculator()

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def calculator():
    def add(x, y):
        return x + y

    def sub(x, y):
        return x - y

    def mul(x, y):
        return x * y

    def div(x, y):
        return x / y

    def power(x, y):
        return x ** y

    def modulus(x, y):
        return x % y

    print(""" -- Select Operation --
    1. Addition
    2. Subtraction
    3. Multiplication
    4. Division
    5. Power
    6. Modulus
    """)
    from decimal import Decimal
    choice = input("Enter 1 or 2 or 3 or 4 or 5 or 6 from the Select Operation >> ")
    while choice not in ('1', '2', '3', '4', '5', '6'):
        choice = input("Invalid Input! Please Enter 1 or 2 or 3 or 4 or 5 or 6 from the Select Operation >> ")
    print("\n")
    print("============================================================")
    print("Gathering data...")
    # How to make user input in both int and float not int alone?
    num1 = Decimal(input("Enter First number >> "))
    num2 = Decimal(input("Enter Second number >> "))

    if choice == '1':
        print(num1, "+", num2, "=", str(add(num1, num2)))
    elif choice == '2':
        print(num1, "-", num2, "=", str(sub(num1, num2)))
    elif choice == '3':
        print(num1, "*", num2, "=", str(mul(num1, num2)))
    elif choice == '4':
        print(num1, "/", num2, "=", str(div(num1, num2)))
    elif choice == '5':
        print(num1, "^", num2, "=", str(power(num1, num2)))
    elif choice == '6':
        print(num1, "%", num2, "=", str(modulus(num1, num2)))
    repeat_cal()

def repeat_cal():
    print("Do you want to Select Operation again")
    choose_again = input("Enter Y for YES or N for NO>> ")
    if choose_again.upper() == 'Y':
        calculator()
    elif choose_again.upper() == 'N':
        print("-----------------Good Bye!---------------------------")
        exit()
    else:
        repeat_cal()

calculator()