Math 如何计算循环所需的元素？

我有以下数据： y-n-y-y-n-n-n 这会无限重复，例如： y-n-y-y-n-n-n-y-n-n-n-n-y-n-n-y-n-n-n-n-n-n-n-n-n-n-n

我有5“x”。 “x”只跟“y”在一起。 也就是说，如果我在上面的循环中分配x，它将是：

y-n-y-y-n-n-n-y-n-y-n-n-n-n

x--x-x--x-x

我想数一数我需要使用多少个循环元素来分布5x，答案是10

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我怎么用公式计算呢？

我想你说的是，你需要处理无限列表的前10个元素，得到5个Y，与你拥有的5个X相匹配

y-n-y-y-n-n-n-y-n-y-y-n-n-n-y-n-y-y-n-n-n... 
x-_-x-x-_-_-_-x-_-x 
                  ^
                  L____ 10 elements read from the infinite list to place the 5 x's. 

我还假设您的问题是：给定5X的输入，您需要在无限列表中处理多少个元素来匹配这些5X

您可以使用类似以下伪代码的循环来计算它：

iElementsMatchedCounter = 0 
iXsMatchedCounter = 0 
iXLimit = 5 
strElement = "" 

if (InfiniteList.IsEmpty() == false) 
{ 
    do 
    { 
        strElement = InfiniteList.ReadNextElement()

        if (strElement == "y") 
        { 
            iXsMatchedCounter += 1 
        } 

        iElementsMatchedCounter += 1 

    } while ( (InfiniteList.IsEndReached() == false) AND (iXsMatchedCounter < iXLimit) ) 
} 

if (iXsMatchedCounter = iXLimit) 
    then Print(iElementsMatchedCounter) 
    else Print("End of list reached before all X's were matched!") 

---

你能把你的问题解释清楚吗？

iQuotient = iNumberOfXs / iNumberOfYsInSubList     // COMMENT: here integer division automatically drops the remainder 
iPartialLengthOfList = iQuotient * iLengthOfSubList 

iPendingXs = iNumberOfXs  - (iQuotient  * iNumberOfYsInSubList) 
// COMMENT: can use modulo arithmetic like the following to calculate iPendingXs 
// iPendingXs = iNumberOfXs % iNumberOfYsInSubList 

// The following IF statement assumes the sub-list to be y-n-y-y-n-n-n 
if (iPendingXs > 1) 
    then iPendingLengthOfList = iPendingXs + 1 
    else iPendingLengthOfList = iPendingXs 

iResult = iPartialLengthOfList + iPendingLengthOfList