Python 给定两个角，求三角形两边的长度，以及它们之间边的长度

我试着用相同的参数来模拟一个函数，但得到的结果不同

def getTwoSidesOfASATriangle(a1, a2, s):
    '''
    Get the length of two sides of a triangle, given two angles, and the length of the side in-between.

    args:
        a1 (float) = Angle in degrees.
        a2 (float) = Angle in degrees.
        s (float) = The distance of the side between the two given angles.

    returns:
        (tuple)
    '''
    from math import sin

    a3 = 180 - a1 - a2

    result = (
        (s/sin(a3)) * sin(a1),
        (s/sin(a3)) * sin(a2)
    )

    return result

d1, d2 = getTwoSidesOfASATriangle(76, 34, 9)
print (d1, d2)

---

感谢@Stef为我指明了正确的方向。下面是一个工作示例，以防对将来的人有所帮助

def getTwoSidesOfASATriangle(a1, a2, s, unit='degrees'):
    '''
    Get the length of two sides of a triangle, given two angles, and the length of the side in-between.

    args:
        a1 (float) = Angle in radians or degrees. (unit flag must be set if value given in radians)
        a2 (float) = Angle in radians or degrees. (unit flag must be set if value given in radians)
        s (float) = The distance of the side between the two given angles.
        unit (str) = Specify whether the angle values are given in degrees or radians. (valid: 'radians', 'degrees')(default: degrees)

    returns:
        (tuple)
    '''
    from math import sin, radians

    if unit is 'degrees':
        a1, a2 = radians(a1), radians(a2)

    a3 = 3.14159 - a1 - a2

    result = (
        (s/sin(a3)) * sin(a1),
        (s/sin(a3)) * sin(a2)
    )

    return result

---

sin

和

cos

在Python中使用弧度，而不是度。行

a3=180-a1-a2

向我表明，您认为它们使用度。首先必须将角度转换为弧度。尝试执行

a3=数学弧度（180-a1-a2）

。在开始使用函数之前，最好先阅读函数文档：